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Mathematics: Post your doubts here!

salvatore

salvatore

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Dug said:
6x+k = 7√x
Let y = √x
6x^2 - 7y + k = 0

b^2 - 4ac = 0 (Since its a tangent)
(-7)^2 - 4(6)(k) = 0
k = 49/24
Click to expand...
Thank you for your reply.
I don't understand how you got 6x^2.. isn't it 6x in the equation?
 
Dug

Dug

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salvatore said:
I'm really sorry for bothering, but i still don't understand how you solved it.. especially the part where you got 6y^2.
Please help me understand it.
Thanks
Click to expand...
Don't be. I only used the substitution to make u realize that the equation was actually quadratic. Do you still not get it?
 
Dug

Dug

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Jspake said:
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s12_qp_12.pdf
I completely don't understand how to solve question no. 7.
Please explain the solution.. thanks a lot
Click to expand...
a)
Sn = n^2 +8n
S1 = a1, since the sum of the first term will be only the first term.
So proceeding to find a1:
S1 = 1 + 8 = 9

Now we know that,
a1 = a
a2 = a + d

S2 = 4 + 16 = 20

Also, S2 = a1 + a2
S2 = a + (a + d)
20 = 9 + (9 + d)
d = 2

b)
According to the statement:
a2 = a1 - 9
ar - a = - 9
a(r-1) = -9
a = -9/(r-1) ------ i

And,
a2 + a3 = 30
ar + ar^2 = 30 -------- ii

We have a system of equations.

Put i in ii, you will get 'r' and consequently 'a'.
 
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PhyZac

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Assalamu Alikum Wa Rahmatullahi Wa Barakatoho.................


Can anyone solve this, please?

Integrate 4/(x+1)^2
 
Dug

Dug

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PhyZac said:
Assalamu Alikum Wa Rahmatullahi Wa Barakatoho.................


Can anyone solve this, please?

Integrate 4/(x+1)^2
Click to expand...
Walaikum AsSalam Warahmatullahi Wabarakatohu

⌡4/(x+1)^2 dx
= 4⌡(x+1)^-2 dx
= 4 [(x+1)^-2+1 /-1] + C
= -4/(x+1) + C
 
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PhyZac

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Dug said:
Walaikum AsSalam Warahmatullahi Wabarakatohu

⌡4/(x+1)^2 dx
= 4⌡(x+1)^-2 dx
= 4 [(x+1)^-2+1 /-1] + C
= -4/(x+1) + C
Click to expand...
Jazaka Allah Khairan....... Thank you so much !! May Allah reward you for your help Ameen, And In Shaa Allah you get the highest results in this world and hereafter Ameen!
 
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Dug

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PhyZac said:
Jazaka Allah Khairan....... Thank you so much !! May Allah reward you for your help Ameen, And In Shaa Allah you get the highest results in this world and hereafter Ameen!
Click to expand...
Wa iyyakum. Thanks for this awesome Dua, for the second time!! :D May He grant you success in this world and the Hereafter and have mercy on you and your family. May He make these exams easy for you. :)
 
RadzMau

RadzMau

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Hi. Can someone pls help me for this question? :)
-> When the polynomial P(x) is divided by (x-1), the remainder is 5 and when P(x) is divided by (x-2), the remainder is 7. Find the remainder when P(x) is divided by (x-1)(x-2).
 
Dug

Dug

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Iffat said:
Plz help!
2012 may june p11 q5(ii) and q8(i)
p12 q4 and q10
Click to expand...

Q5(ii)

6x+k = 7√x
Let y = √x
6x^2 - 7y + k = 0

b^2 - 4ac = 0 (Since its a tangent)
(-7)^2 - 4(6)(k) = 0
k = 49/24

Q8(i)
x^2 - 4x + k
= x^2 - 4x + (-2)^2 - (-2)^2 + k
= (x - 2)^2 - 4 + k
 
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