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Mathematics: Post your doubts here!

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Can anyone help me out with the b part of this Q. I have my exams tomorrow and I cant figure this out :(Untitled.jpg
 
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Can anyone help me out with the b part of this Q. I have my exams tomorrow and I cant figure this out :(View attachment 22026

(ii) Any unit vector has a magnitude of 1. If AB is a unit vector |AB| = 1
AB = (k -k 2k) - (1 0 2) = (k-1, -k, 2k-2)
|AB| = √{(k-1)^2 + (-k)^2 + (2k-2)^2}
1 = √(k^2 -2k + 1 + k^2 + 4k^2 -8k +4)
1^2 = 6k^2 - 10k +5
1 = 6k^2 - 10k + 5
6k^2 -10k +4 =0
Solve and you get k as 1 and 2/3
 
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they already said leave the answer in surds..so when u do the equation x= -b ±√(b^2-4ac) / 2a u will end up with x =1/4 (-20 + √40) or 1/4(-20-√40) u can simplify it..did u get it now ?
the answer for this question is :
x= (-12+√40)/4 and x=(-12-√40)/4
 
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The amounts of money, x dollars, that 24 people had in their pockets are summarised by Σ(x − 36) = −60 and Σ(x − 36)2 = 227.76. Find Σx and Σx^2\

Does anybody have a guide on how to solve questions like these? They are really confusing :/
 
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Can any1 help with a(ii) ? thanks in advance
 

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Dug

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The amounts of money, x dollars, that 24 people had in their pockets are summarised by Σ(x − 36) = −60 and Σ(x − 36)2 = 227.76. Find Σx and Σx^2\

Does anybody have a guide on how to solve questions like these? They are really confusing :/
Sum of coded values = -60
Σx = -60 + (24*36) = 804

Σ(x-36)^2 = 227.76
Expand LHS:
Σ(x^2 - 72x + 1296) = 227.76
Σx^2 - 72Σx + Σ1296 = 227.76
We have Σx = 804 and Σ1296 = (1296)(24) = 31104
Σx^2 - (804)(72) + 31104 = 227.76
Σx^2 = 27011.76
 
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Can any1 help with a(ii) ? thanks in advance

5ai) For three courses a dish has to be picked from each course.
For the first course there are 3 options so 3C1
For the second course there are 5 options so 5C1. But each dish has two possible choices of being served with either fries or potatoes. So the actual combination is 2* 5C1
For the third course 3C1
Total no of ways = 3C1 * 5C1* 2 *3C1 = 90

ii) Only two courses can be picked. Possible choices - Starter-main, Starter-dessert, Main-dessert
Starter-main= 3C1* 5C1 *2 = 30
Starter-dessert= 3C1*3C1 = 9
Main-dessert= 5C1* 3C1 *2 =30
Total = 30 + 30 +9 =69

b) You have to find the different ways to divide not different arrangements. So, 14C5* 9C5 * 4C4 =252252.
The answer will be the same no matter which table you decide to chose first.
 
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5ai) For three courses a dish has to be picked from each course.
For the first course there are 3 options so 3C1
For the second course there are 5 options so 5C1. But each dish has two possible choices of being served with either fries or potatoes. So the actual combination is 2* 5C1
For the third course 3C1
Total no of ways = 3C1 * 5C1* 2 *3C1 = 90

ii) Only two courses can be picked. Possible choices - Starter-main, Starter-dessert, Main-dessert
Starter-main= 3C1* 5C1 *2 = 30
Starter-dessert= 3C1*3C1 = 9
Main-dessert= 5C1* 3C1 *2 =30
Total = 30 + 30 +9 =69

b) You have to find the different ways to divide not different arrangements. So, 14C5* 9C5 * 4C4 =252252.
The answer will be the same no matter which table you decide to chose first.

thanks a lot:)
 
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Sum of coded values = -60
Σx = -60 + (24*36) = 804

Σ(x-36)^2 = 227.76
Expand LHS:
Σ(x^2 - 72x + 1296) = 227.76
Σx^2 - 72Σx + Σ1296 = 227.76
We have Σx = 804 and Σ1296 = (1296)(24) = 31104
Σx^2 - (804)(72) + 31104 = 227.76
Σx^2 = 27011.76
I understood the Σx part, but not the Σx^2 part :/ Why did you do that?
 

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I understood the Σx part, but not the Σx^2 part :/ Why did you do that?
I expanded Σ(x-36)^2 it to pull out the term Σx^2. That is what we are supposed to find.

Consider this example:

(a+b)^2 = 4
a^2 + 2ab + b^2 = 4

If we are given 'ab' and 'b^2', we can easily find a^2 by putting the values into the equation. My solution is exactly the same. Did you get it now?
 
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Assalamualikum
Can someone please help me with question 7(ii), 8(i) & 11(ii).
Thanks a bunch in advance. (y)
 

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