Mathematics: Post your doubts here!

[A star]

Assalamoalaikum Wr Wb!

Post your doubts here. Make sure you give the link to the question paper when posting your doubts.


May Allah give us all success in this world as well as the HereAfter...Aameen!!

And oh yeah, let me put up some links for A level Maths Notes here.

Check this out! - Nice website, with video tutorials for everything! MUST CHECK

My P1 Notes! - Only few chapters available at the moment!

Maths Notes by destined007

Some Notes for P1 and P3 - shared by hamidali391

A LEVEL MATHS TOPIC WISE NOTES

MATHS A LEVEL LECTURES

compiled pastpapers p3 and p4 - by haseebriaz

Permutations and Combinations (my explanation)- P6

Permutations and Combinations - P6

Vectors - P3

Complex No. max/min IzI and arg(z) - P3

Sketcing Argand Diagrams - P3 (click to download..shared by ffaadyy)

Range of a function. - P1

guys this might help

 

[littlecloud11]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_qp_33.pdf

10 (i)
Thanks!

Dug iKhaled or anyone.

 

[PhyZac]

guys any one know that if there will be a deduction of mark if we directly solve quadratic equation from the calculator and just write down the answer without showing our steps

You better show your working, in every thing.
You do want to risk your marks, atleast this paper!

May Allah S.W.T grant us all success in this paper, Aameen.

 

[daredevil]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_w10_qp_12.pdf

hey has anyone answered this question 7 from this paper cz i forgot if u did can u guyss explain it to me esp the last part or if u have already done that then just tell me where u did that thnx

 

[Sarah22]

for 7(iii)
f(x)=(x-2)^2+3
f=hg
h(g(x))=(x-2)^2+3
h(g(x))=(g(x))^2+3, take g(x)=x
h(x)=x^2+3
Thank you very much.. But I dont understand why you took g(x)=x

 

[daredevil]

thnakkks

 

[snowbrood]

thnakkks

Prove the identity (sin x + cos x)(1 − sin x cos x) ≡ sin3 x + cos3 x. [3]
(ii) Solve the equation (sin x + cos x)(1 − sin x cos x) = 9 sin3 x for 0◦ ≤ x ≤ 360◦. can anyone solve part (ii) i dont get it @A

 

[Sarah22]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w10_qp_12.pdf

hey has anyone answered this question 7 from this paper cz i forgot if u did can u guyss explain it to me esp the last part or if u have already done that then just tell me where u did that thnx

(i) f(x)=x^2-4x+7
For this you can follow the usual method,
(x-2)^2-4+7
(x-2)^2+3
Range is: f(x)>=3. You can see this form the answer (x-2)^2+3

(ii) f−1(x)=y
y=(x-2)^2+3
square root of y-3=x-2
x=square root of (y-3)+2
then you interchange x with y
y=square root of (x-3)+2, which is your f-1(x)

 

[PhyZac]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_qp_33.pdf

10 (i)
Thanks!

Dug iKhaled or anyone.

I tried my best to understand, but it is hard. I found this.
https://www.xtremepapers.com/commun...st-your-doubts-here.9599/page-323#post-485476

 

[A star]

thnakkks

canu answer my wuestion :/

 

[PANDA-]

Prove the identity (sin x + cos x)(1 − sin x cos x) ≡ sin3 x + cos3 x. [3]
(ii) Solve the equation (sin x + cos x)(1 − sin x cos x) = 9 sin3 x for 0◦ ≤ x ≤ 360◦. can anyone solve part (ii) i dont get it @A

Take sin3x + cos3x as (sinx + cosx)(1 - sinx cosx)
So you get...
sin3x + cos3x = 9sin3x

Divide both sides by sin3x

1 + cos3x/sin3x = 9
1 + tan3x = 9
tan 3x = 8
3x = tan^-1(8)
x= 27.6 <=== Is this correct?

 

[littlecloud11]

I tried my best to understand, but it is hard. I found this.
https://www.xtremepapers.com/commun...st-your-doubts-here.9599/page-323#post-485476

Thank you Thank you Thank you!
I got it.

 

[snowbrood]

Take sin3x + cos3x as (sinx + cosx)(1 - sinx cosx)
So you get...
sin3x + cos3x = 9sin3x

Divide both sides by sin3x

1 + cos3x/sin3x = 9
1 + tan3x = 9
tan 3x = 8
3x = tan^-1(8)
x= 27.6 <=== Is this correct?

answer is 26.6

 

[A star]

Prove the identity (sin x + cos x)(1 − sin x cos x) ≡ sin3 x + cos3 x. [3]
(ii) Solve the equation (sin x + cos x)(1 − sin x cos x) = 9 sin3 x for 0◦ ≤ x ≤ 360◦. can anyone solve part (ii) i dont get it @A

is it p1?

 

[snowbrood]

Take sin3x + cos3x as (sinx + cosx)(1 - sinx cosx)
So you get...
sin3x + cos3x = 9sin3x

Divide both sides by sin3x

1 + cos3x/sin3x = 9
1 + tan3x = 9
tan 3x = 8
3x = tan^-1(8)
x= 27.6 <=== Is this correct?

lol chutia me i have solved this on my own now thanks anyways

 

[snowbrood]

is it p1?

yea p1 dude

 

[A star]

i

yea p1 dude

am also gettting 26.6. what year did u take it from?

 

[haha101]

Guys . tommorow we all have P1 . So i was thinking why dont we share some tips that help us in solving papers . Let me the first to initiate :

1. co linear or parallel vectors have a ratio of k . E.G if a and b are co linear then a^/b^ =k .

 

[A star]

Guys . tommorow we al have P1 . So i was thiinking why dont we share some tips that hepl us in solving papers . Let me the first to initiate :

1. colinear of parallell vectors have a ratio of k . EG if a and b are colinear then a^/b^ =k .

what?

 

[PANDA-]

Guys . tommorow we al have P1 . So i was thiinking why dont we share some tips that hepl us in solving papers . Let me the first to initiate :

1. colinear of parallell vectors have a ratio of k . EG if a and b are colinear then a^/b^ =k .

I didn't get it.