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Mathematics: Post your doubts here!

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Assalamoalaikum Wr Wb!

Post your doubts here. Make sure you give the link to the question paper when posting your doubts.


May Allah give us all success in this world as well as the HereAfter...Aameen!!

And oh yeah, let me put up some links for A level Maths Notes here.

Check this out! - Nice website, with video tutorials for everything! MUST CHECK

My P1 Notes! - Only few chapters available at the moment!

Maths Notes by destined007

Some Notes for P1 and P3 - shared by hamidali391

A LEVEL MATHS TOPIC WISE NOTES

MATHS A LEVEL LECTURES

compiled pastpapers p3 and p4 - by haseebriaz

Permutations and Combinations (my explanation)- P6

Permutations and Combinations - P6

Vectors - P3

Complex No. max/min IzI and arg(z) - P3

Sketcing Argand Diagrams - P3 (click to download..shared by ffaadyy)

Range of a function. - P1
any guess paper for p1 a levels maths???
 
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Cosπ/6= 16/hypotenuse
Which gives the hypotenuse as 18 something. Which is wrong, it's not a right angle triangle :c
hypotenuse AC is itself 16. cos(pi/6)=BC/AC which gives BC = 8*3^(1/2). sin(pi/6)=AB/AC which gives AB=8. The perimeter is (8+16+8*3^(1/2)) which is what the question requires us to show. Angle B is 90 degree because AC is the diameter and B is on the circumcircle. :) (I could give a mathematical proof of why ABC is right angled)
 
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Into the equation of straight line "y-y1=m(x-x1)"

Ah, gotcha' . I udnerstood the rest as well, thanks =)


hypotenuse AC is itself 16. cos(pi/6)=BC/AC which gives BC = 8*3^(1/2). sin(pi/6)=AB/AC which gives AB=8. The perimeter is (8+16+8*3^(1/2)) which is what the question requires us to show. Angle B is 90 degree because AC is the diameter and B is on the circumcircle. :) (I could give a mathematical proof of why ABC is right angled)

Oh lord, I was taking BC as the hypotenuse for some reason .____. ...
It's late and I'm tired, sorry xD
Both ways work out in the end though, so no harm done.
 
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The first two terms of a geometric progression are 1 and (1/3) tan^2 θ respectively, where 0 < θ < (1/2)π
Find the set of values of θ for which the progression is convergent

INSTANT HELP NEEDED !
covergent progressions are those whose sum of infinity tends to 'zero' but is never zero . they have r<1
 
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Ah, gotcha' . I udnerstood the rest as well, thanks =)




Oh lord, I was taking BC as the hypotenuse for some reason .____. ...
It's late and I'm tired, sorry xD
Both ways work out in the end though, so no harm done.
No problem.
 
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You can't use sin since it's not a right angle triangle.

For finding side AB, you know that angle BOA is 60, and two of your sides are 8. It has to be an equilateral triangle meaning AB is also 8.
For finding BC you just use cos rule using triangle OBC. If you want I can solve it :c


Also, I've got finally got question :3 A star daredevil asd
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s11_qp_13.pdf
Q3.
yeah i thought so, but the markscheme says sin :ROFLMAO:
 
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The function f : x → 4 − 3 sin x is defined for the domain 0 ≤ x ≤ 2p.
(i) Solve the equation f(x) = 2. [3]
(ii) Sketch the graph of y = f(x). [2]
(iii) Find the set of values of k for which the equation f(x) = k has no solution. [2]
HOW DO YOU DO PART 3?o_O
 

asd

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Ah, gotcha' . I udnerstood the rest as well, thanks =)




Oh lord, I was taking BC as the hypotenuse for some reason .____. ...
It's late and I'm tired, sorry xD
Both ways work out in the end though, so no harm done.
Np. :)
Okay guys, im off to bed now.
BEST OF LUCK EVERYBODY! :)
 
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Yo guys i really need your help on this one part iii Q9

Now why is Vice City on your Task Bar :D Supposed to be exam time :p

Anyway.. the midpoint of AC is equal to the midpoint of DB, as diagonals bisect each other.
I think you can figure out the rest.
 
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Any Help>
a beetle starts from o and walk 0.6 m east and then 0.36 m west and then 0.216 east and so on ..
find its final position .. its a GP PANDA-
 
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Now why is Vice City on your Task Bar :D Supposed to be exam time :p

Anyway.. the midpoint of AC is equal to the midpoint of DB, as diagonals bisect each other.
I think you can figure out the rest.

YO.. did ya get that Limits thingy? the 0<x<k question... If yes then .. explain it to me :p
 
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:unsure: Guys till how many significant figures should we round our answers in the paper tomorrow ..!! pleasse..quick.:confused:
 
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:unsure: Guys till how many significant figures should we round our answers in the paper tomorrow ..!! pleasse..quick.:confused:

'Give non-exact numerical answers correct to 3 significant figures, or 1 decimal place in the case of angles in
degrees, unless a different level of accuracy is specified in the question.'

It's written on the front of every paper =)
 
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