Mathematics: Post your doubts here!

[shezi1995]

You can't use sin since it's not a right angle triangle.

For finding side AB, you know that angle BOA is 60, and two of your sides are 8. It has to be an equilateral triangle meaning AB is also 8.
For finding BC you just use cos rule using triangle OBC. If you want I can solve it :c


Also, I've got finally got question :3 A star daredevil asd
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s11_qp_13.pdf
Q3.

ABC is a right angled triangle. Angle subtended by diameter is always 90 degree. So angle ABC is 90. angle c will be half of (pi/3) that is (pi/6). so you just use sin and cos with the hypotenuse AC equal to 16. So no need to use cosine rule and stuff. It is just o level maths knowledge.

 

[ShreeyaBeatz]

The first two terms of a geometric progression are 1 and (1/3) tan^2 θ respectively, where 0 < θ < (1/2)π
Find the set of values of θ for which the progression is convergent

INSTANT HELP NEEDED !

 

[A star]

well guys goodluck and happy tutoring rest of them daredevil

 

[Rutzaba]

agh.. I am tensed :/ I DONT FUKIN WANNA BE ....UGHHH

its going to be ok in sha Allah... have faith in urself and the Almighty

 

[Rutzaba]

wats wrong wth u guys... i had clashes... and then i was giving accelerated... and that was wen i paniced just keep calm and say Alhamdulilah!

 

[ZainH]

ABC is a right angled triangle. Angle subtended by diameter is always 90 degree. So angle ABC is 90. angle c will be half of (pi/3) that is (pi/6). so you just use sin and cos with the hypotenuse AC equal to 16. So no need to use cosine rule and stuff. It is just o level maths knowledge.

Cosπ/6= 16/hypotenuse
Which gives the hypotenuse as 18 something. Which is wrong, it's not a right angle triangle :c

 

[ZainH]

Oh, dude I just did it yest. D
P(a,0)
Q(0,b)
now the distance PQ= [a^2 + b^2]^1/2 = 45^1/2
a^2+b^2=45.
substituting (a,0), y=-1/2 (x + a)
2y=a-x ---> (i)
Now substituting (b,0), y-b=-1/2(x-o)
2y= 2b-x ---> (ii)
a-x=2b-x
a=2b
Now plug in the value of a in the distance equation to get the values.

I understood up until , a²+b² = 45 ..

Now what are you substituting your values into?

 

[daredevil]

The first two terms of a geometric progression are 1 and (1/3) tan^2 θ respectively, where 0 < θ < (1/2)π
Find the set of values of θ for which the progression is convergent

INSTANT HELP NEEDED !

Ok r<1 then progression is convergent. So use that in here however u can cz i cant solve ryt now sorry

 

[asd]

I understood up until , a²+b² = 45 ..

Now what are you substituting your values into?

Into the equation of straight line "y-y1=m(x-x1)"

 

[hamayal]

Assalamoalaikum Wr Wb!

Post your doubts here. Make sure you give the link to the question paper when posting your doubts.


May Allah give us all success in this world as well as the HereAfter...Aameen!!

And oh yeah, let me put up some links for A level Maths Notes here.

Check this out! - Nice website, with video tutorials for everything! MUST CHECK

My P1 Notes! - Only few chapters available at the moment!

Maths Notes by destined007

Some Notes for P1 and P3 - shared by hamidali391

A LEVEL MATHS TOPIC WISE NOTES

MATHS A LEVEL LECTURES

compiled pastpapers p3 and p4 - by haseebriaz

Permutations and Combinations (my explanation)- P6

Permutations and Combinations - P6

Vectors - P3

Complex No. max/min IzI and arg(z) - P3

Sketcing Argand Diagrams - P3 (click to download..shared by ffaadyy)

Range of a function. - P1

any guess paper for p1 a levels maths???

 

[shezi1995]

Cosπ/6= 16/hypotenuse
Which gives the hypotenuse as 18 something. Which is wrong, it's not a right angle triangle :c

hypotenuse AC is itself 16. cos(pi/6)=BC/AC which gives BC = 8*3^(1/2). sin(pi/6)=AB/AC which gives AB=8. The perimeter is (8+16+8*3^(1/2)) which is what the question requires us to show. Angle B is 90 degree because AC is the diameter and B is on the circumcircle. (I could give a mathematical proof of why ABC is right angled)

 

[ZainH]

Into the equation of straight line "y-y1=m(x-x1)"

Ah, gotcha' . I udnerstood the rest as well, thanks =)

hypotenuse AC is itself 16. cos(pi/6)=BC/AC which gives BC = 8*3^(1/2). sin(pi/6)=AB/AC which gives AB=8. The perimeter is (8+16+8*3^(1/2)) which is what the question requires us to show. Angle B is 90 degree because AC is the diameter and B is on the circumcircle. (I could give a mathematical proof of why ABC is right angled)

Oh lord, I was taking BC as the hypotenuse for some reason .____. ...
It's late and I'm tired, sorry xD
Both ways work out in the end though, so no harm done.

 

[HorsePower]

The first two terms of a geometric progression are 1 and (1/3) tan^2 θ respectively, where 0 < θ < (1/2)π
Find the set of values of θ for which the progression is convergent

INSTANT HELP NEEDED !

covergent progressions are those whose sum of infinity tends to 'zero' but is never zero . they have r<1

 

[shezi1995]

Ah, gotcha' . I udnerstood the rest as well, thanks =)




Oh lord, I was taking BC as the hypotenuse for some reason .____. ...
It's late and I'm tired, sorry xD
Both ways work out in the end though, so no harm done.

No problem.

 

[Rizwanjubail]

Plz can some1 explain Question no.11 part (iii) of this year http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_s09_qp_1.pdf
Plz its urgent,I have exam after around 14 hours

 

[sma786]

You can't use sin since it's not a right angle triangle.

For finding side AB, you know that angle BOA is 60, and two of your sides are 8. It has to be an equilateral triangle meaning AB is also 8.
For finding BC you just use cos rule using triangle OBC. If you want I can solve it :c


Also, I've got finally got question :3 A star daredevil asd
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s11_qp_13.pdf
Q3.

yeah i thought so, but the markscheme says sin

 

[xxxt]

The function f : x → 4 − 3 sin x is defined for the domain 0 ≤ x ≤ 2p.
(i) Solve the equation f(x) = 2. [3]
(ii) Sketch the graph of y = f(x). [2]
(iii) Find the set of values of k for which the equation f(x) = k has no solution. [2]
HOW DO YOU DO PART 3?

 

[asd]

Ah, gotcha' . I udnerstood the rest as well, thanks =)




Oh lord, I was taking BC as the hypotenuse for some reason .____. ...
It's late and I'm tired, sorry xD
Both ways work out in the end though, so no harm done.

Np.
Okay guys, im off to bed now.
BEST OF LUCK EVERYBODY!

 

[ZainH]

yeah i thought so, but the markscheme says sin

Screw the mark scheme ;o

Np.
Okay guys, im off to bed now.
BEST OF LUCK EVERYBODY!

Night dude, best of luck!

 

[sma786]

Express 8x−x^2 in the form a− (x+b)^2
Help pleasE?