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Thanx! n Best of luck 4 M1 2mrw!!!Will try this one after mechanics...though it looks like a simple differential equations question
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Thanx! n Best of luck 4 M1 2mrw!!!Will try this one after mechanics...though it looks like a simple differential equations question
Is a=gsintheta a rule ??
What they have given us:The 'x' components of the following forces:Nov012 v.42 no4 :S
What they have given us:The 'x' components of the following forces:
68 N = -60N
75N= 0N
100N= 96N,
What we gotta find, i) (resolve the forces 100 N and 68N) therefore, 68cos(theta) = -60 , theta= 28.1 deg
100cos (beta) =96, beta=16.2 deg, hence we now know the angles that the forces make with the horizontal axis. We can find 'y' components of the forces.
68 N => -68sin28.1 = -32 N ( negative as it in he the negative y axis direction)
75 N => no components to resolve as it is itself on the y-axis so, 75 N
100 N => -100sin16.2= -27.9 N
ii) List the Fx components of the forces And then the Fy components as we calculated above:
Fx=> -60+0+96 = 36 N
Fy=> -32+75-27.9= 15.1 N
Resultant = (36^2 + 15.1^2)^1/2 (i took the square root of the squares of the sum of the two forces we calculated (Fx and Fy)
Therefore, tan(theta)= y/x => tan (theta) = 15.1/36, theta= 22.8 deg.
Hope u got it.
Okaaay thankswhen there is no frictional force then the formula is applicable
They should accept the registration to download right ?
They should accept the registration to download right ?
Emm, I registered and there's no email in my inbox.yes! u wil get an email!
please no.7 v.42 iv.
please no.7 v.42 iv.
yea i have this
Nov 2012 .Paper?
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