- Messages
- 1,601
- Reaction score
- 553
- Points
- 123
InshaAllahNovember 2012 P3, was the hardest paper which CIE released since 2002 !
Lets hope we get one which will be much easier tomorrow so that we all can ace Insha Allah
We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
Click here to Donate Now (View Announcement)
InshaAllahNovember 2012 P3, was the hardest paper which CIE released since 2002 !
Lets hope we get one which will be much easier tomorrow so that we all can ace Insha Allah
the easier the harder to ace to harder the easier to aceNovember 2012 P3, was the hardest paper which CIE released since 2002 !
Lets hope we get one which will be much easier tomorrow so that we all can ace Insha Allah
I see. Thank you so much.You found your limit in part i, which was 1/4 π. Now as you can see, before the area under the curve was denoted by A. Now they equated the integral to 40A, which means the area under the curve is 40 times bigger. Hence the limits are to be multiplied by 40.
kπ= 1/4π *40
k=10
I get! Thanks a lot man!Dude, just multiply your two answers from part i) to get one quadratic factor and find the other one by (Ax^2 + Bx + C) inspection.
That is, the roots you get in i) are 1 - √2 i and 1 + √2 i. So the factors become (x-1+√2 i)(x-1-√2 i). You multiply the brackets and you'll see everything in terms of 'i' gets cancelled to give you a quadratic factor of x^2 - 2x +3.
If you still don't get it, let me know I'll post a screenshot.
OMGG THAT EXPLAINS IT ALL!!Hey, you switched your axis! You put the imaginary one in the real one!
I KNOW RITE !!!What's driving me insane is, what in the world were they thinking sticking maths and chemistry in one day? And Stats and physics p4 two days later? They're HUGE papers- it's like they WANT us to do bad.
This meme makes SO much sense now:
i have a feeling a question of this type is coming tomorrow..pls can someone fully explain it question 10 second parthttp://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w10_qp_33.pdf
please help me in detail with 10 (2) b, where we have to find 6 roots. I don't understand what the mark scheme says.
i have a feeling a question of this type is coming tomorrow..pls can someone fully explain it question 10 second part
t
the easier the harder to ace to harder the easier to ace
Thanks A lot man .. it helpedw= -1 + i (on diagram (-1,1))
w^2 = -2i (on diagram (0,-2))
midpoint = ((-1+0)/2, (1-2)/2)
(-1/2 , -1/2) = -0.5 -0.5i
yeah ik but being so easy is the worst because i am one of these dudes who can make so many silly mistakes because of exam stress lolThe paper being too hard is not so good sometimes !
Because in the exam hall, you might get confused and you are stressed ! Then, you start messing around ! :s
no bro i didn't get it :/ can u show the solution of this question..only the last part plsthis is functions bro ....
P(x) = x^2 + 2x +3
P(1) = 1 + 2 + 3 = 6
p(x^2) = (x^2)^2 + 2 (x^2) + 3
now try to do that question
hope yu get it . ....
were yu able to do first part .. ?no bro i didn't get it :/ can u show the solution of this question..only the last part pls
yes i got all of the question but i don't know how to deal with the 6 roots thingy i cant get this questionwere yu able to do first part .. ?
ohkay makes my work easy wait ..yes i got all of the question but i don't know how to deal with the 6 roots thingy i cant get this question
Agreed ! same here !yeah ik but being so easy is the worst because i am one of these dudes who can make so many silly mistakes because of exam stress lol
For almost 10 years, the site XtremePapers has been trying very hard to serve its users.
However, we are now struggling to cover its operational costs due to unforeseen circumstances. If we helped you in any way, kindly contribute and be the part of this effort. No act of kindness, no matter how small, is ever wasted.
Click here to Donate Now