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yeah it was a riot -_-
i was like #)$*#@)%()$@!&%!@#)$( through the whole paper X_X It felt like i was doing p3 for the first friggin time... i've forgotten everrrything!!! :O :O :O
Yar sorry stupid xpc didnt seem yo work. I have a project to submit by next week!!!
yeah sure.... take ur time =)
q.4(ii) .. initial value is not given so choose eg, pi/4 and plug it in the equation given .
then you 1.32 ( radians measure ) , plug this in equation and you get value , and plug in eqn again till you get a constant value of 1.33.
q.5(ii) we got dy/dx = 2sin^2 t *cos^2 t .. so to find gradient of tangent we need to substitute t value in dy/dx ..
we are given x - value ( 0 ) .. so find t value by substituting x=o in x=ln(tant) ,, we get t =1/4 pi .
. substitute in dy/dx to get gradient of tanget .. so get gradient = 0.5 .. use y=mx +c to find C .. hence you get eqn .
q.7(b) for |z| < 2 draw circle with centre at origin and radius =2
for |z − 2 − 2i|. arrange to make z - ( ... ) so becomes z - ( 2 +2i ) .. draw at 2+2i ..real 2 and imaginery 2 ..and join to origin ...
thats where i can help
Which paper is this question from?Complex numbers question.
I would like some help with understanding how to interpret these three points and place them on a diagram, and perhaps then calculating the area of the thus formed triangle.
Thanks in advance. View attachment 37097
please help me with these questions http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s11_qp_61.pdf Q3you're welcome![]()
Which paper is this question from?
haha not possible i am knee seep in trouble -_- stupid computingooh yeah okay.... take your time... i got the answer to a couple of questions already (see above)
buss saturday ko paper hai uss se pehley if possible to bata dena
otherwise... ah well fail to hona hi hai mocks mein![]()
oohh damn... well khair hai... no probhaha not possible i am knee seep in trouble -_- stupid computing
From what I've understood...Complex numbers question.
I would like some help with understanding how to interpret these three points and place them on a diagram, and perhaps then calculating the area of the thus formed triangle.
Thanks in advance. View attachment 37097
The e^ix +1 = 0 (Euler's identity) is actually derived from euler's formula ye^ix = y(cosx + isinx).
Thanks alot for simplification.
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