Mathematics: Post your doubts here!

[Champ101]

Hey guys is there any resource to get MATHS P3 notes ? I really dont understand vectors and complex numbers. :\

 

[Champ101]

Hey guys can anyone solve this? I just don't get it :\ even after looking through the ms, i didn't get it. Pls someone explain...

 

[yara]

MATH A2 PAPER 3 2013 OCTOBER

PLEase reply

 

[midha.ch]

View attachment 37720

Hey guys can anyone solve this? I just don't get it :\ even after looking through the ms, i didn't get it. Pls someone explain...

Year and paper number+variant ?

 

[daredevil]

Hey guys is there any resource to get MATHS P3 notes ? I really dont understand vectors and complex numbers. :\

here u go.... i don't remember where i found these notes (probably somewhere here on xpf) but they helped me quite a lot with my p1 and p3.... hope it helps...

 

[A star]

^those are useless for p3 -_- . try searchin online you will get them or buy the cie endorsed book for p3 that helps.

 

[yara]

A particular solution of the differential equation

3 y^2 dy/dx=4 ( y^3 + 1 )cos^2(x)

is such that y = 2 when x = 0. The diagram shows a sketch of the graph of this solution for 0 ≤ x ≤ 20;
the graph has stationary points at A and B. Find the y-coordinates of A and B, giving each coordinate
correct to 1 decimal place.

october november 2013 paper 33

 

[yara]

please some one explain how we get to the answer by steps

 

[daredevil]

^those are useless for p3 -_- . try searchin online you will get them or buy the cie endorsed book for p3 that helps.

then find me some good ones and help me with this stuf....

how desperate am i that i find help for maths in some sucky notes _-_
on a serious note though... i did integration and differentiation recently from these starting from the very basics (P1) and working towards almost the end and felt like it did help me....

 

[ahmed abdulla]

then find me some good ones and help me with this stuf....

how desperate am i that i find help for maths in some sucky notes _-_
on a serious note though... i did integration and differentiation recently from these starting from the very basics (P1) and working towards almost the end and felt like it did help me....

where are your doubts

 

[Champ101]

Year and paper number+variant ?

9709/31/M/J/13 - question 7

 

[yara]

why no body answers any question !

 

[Champ101]

If P(x) =x^3 - 12x +16

then what is P(x^2) ? any help

 

[Ren Poole]

Anyone please help.
9709/ 32/MJ/10 question no.8

 

[midha.ch]

If P(x) =x^3 - 12x +16

then what is P(x^2) ? any help

it's quite simple
if it was given P(2), you would have substituted 2 in the equation
same way, now put x^2 in place of x in the equation
that gives you
P(x^2) = (x^2)^3 - 12(x^2) + 16
= x^6 -12x^2 + 16

 

[midha.ch]

A particular solution of the differential equation

3 y^2 dy/dx=4 ( y^3 + 1 )cos^2(x)

is such that y = 2 when x = 0. The diagram shows a sketch of the graph of this solution for 0 ≤ x ≤ 20;
the graph has stationary points at A and B. Find the y-coordinates of A and B, giving each coordinate
correct to 1 decimal place.

october november 2013 paper 33

I don't have a copy of o/n 2013 papers yet. Can you attach the paper and repost??

 

[midha.ch]

Anyone please help.
9709/ 32/MJ/10 question no.8

things I didn't mention in the picture
cos2x = 2(cosx)^2 - 1
1+cos2x = 2(cosx)^2
I directly substituted this in the sum while finding both modulus and argument

and the last line about getting theta for argument
it's easy to understand how tan inverse of tanx = x
(I used x for angle)

 

[sitooon]

I don't have a copy of o/n 2013 papers yet. Can you attach the paper and repost??

This is the link for oct/nov papers!

i actually also had a doubt in this : http://maxpapers.com/category/quali...l/cambridge/a-level/a-level-mathematics-9709/

 

[midha.ch]

Anyone please help.
9709/ 32/MJ/10 question no.8

from the last line you can prove the real part of 1/z is constant i.e. 1/2

 

[daredevil]

where are your doubts

ummm i'll find them again.... forgot what they were XD i'll start doing papers again and come back to u