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Mathematics: Post your doubts here!

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Maths doubt of stem and leaf diagram, please help

Answer is also given in the picture in the smaller font

Thanks a tonne!
Median = Mid-term
we find the nth term where median lies using total number of terms
we have 71 insects for X (odd number)
so Median = {(71+1)/2}th term
= 36th term
start adding up the numbers on the left given in bracket
that's your frquency for the certain range
you"ll have 28th-44th term on the left side of 82 on the stem
5||82 is your median i.e. 0.835

Interquartile range = lower quartie - upper quartile
lower quartile = 25th percentile = {(25/100)x(71+2)}th term
= 18th term
= 0.814
upper quartile = 75th percentile = {(75/100)x(71+2)}th term
= 54th term
= 0.833
thus, IQ = 0.833-0.814 = 0.019
 
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A is basically the amplitude so 9-3
B follows the formula 2pi/B=the period of the wave which in this case is pi ...so re arrange the Formula making B the subject to get 2..... C is basically the shift from the mean axes if u notice the wave is 3 places up from the x axis....
Hope it helps!
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s09_qp_1.pdf
in question 4 i
why do we do 360/180=2 to get B
and 9-3 to get A
6+x=9 to get C
PLEASSEEEE ANSWER AS SOON AS POSSILBE
 
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The formula to calculate median (50th percentile or any other percentile) without the cumulative frequency curve is :

lower class boundary +
((50n/100 - cf (till prev. class)/ f (of that interval))

where n is the total number of observed items or maximum cumulative frequency. First calculate the corresponding class by checking in which class the n/2th value lies then perform the relative ascribed function
Can you please plug in the values given in the table for any one country cause I am a little confused...

Thank you so much for the time and effort
 
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Median = Mid-term
we find the nth term where median lies using total number of terms
we have 71 insects for X (odd number)
so Median = {(71+1)/2}th term
= 36th term
start adding up the numbers on the left given in bracket
that's your frquency for the certain range
you"ll have 28th-44th term on the left side of 82 on the stem
5||82 is your median i.e. 0.835

Interquartile range = lower quartie - upper quartile
lower quartile = 25th percentile = {(25/100)x(71+2)}th term
= 18th term
= 0.814
upper quartile = 75th percentile = {(75/100)x(71+2)}th term
= 54th term
= 0.833
thus, IQ = 0.833-0.814 = 0.019

Thank you so much, but can you solve part (ii) of the question wherein the value of q and r must be deduced?

Thanks once again
 
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Thanks Zaq! Hugely appreciated and I got 2 questions..
1st: Why they are named C1 NOTES even they are P1 NOTES? ;)
2nd: Is there any P1 SHORT notes available for last-minute revision other than these notes?
thanks again. :)(y)
I found them from this site and they were already named C1
I do have this other notes but they aren't that brief this are the only notes i have sorry don't have more short once
 

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I found them from this site and they were already named C1
I do have this other notes but they aren't that brief this are the only notes i have sorry don't have more short once
I can't thank you enough for your help! ;)
If it's OK with you to share that longer notes you have, it will be absolutely amazing! (y)
 
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