Mathematics: Post your doubts here!

[AgentBlank000]

Can someone please help with june 2005 q6 part iii and iv november 2004 q5 part ii?
Thanks in advance

 

[joey978nab]

hello can some one please help with mechanics question june 2011 paper 5 question 7
http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s11_qp_51.pdf

i don't understand the answer from the mark scheme.
thanks in advance

 

[hamza.k143]

Agent blank p3 p1?

 

[immie.rose]

Part (ii) of both questions . . .
I know how to draw argand diagram , but cant figure out how to find K

For the complex no. question. 'k' is the radius. Thence, you need to find the centre of the circle, then calculate the distance between the centre and any one of the points given, i.e. w or w^2.

For the integration question:
You see from part (i) that A= Pi/4
Use cross-multiplication to find k as follows,
A -----> pi/4
40A ------> k Pi

=> k Pi = (40A*pi/4)/ A
A cancels out. k Pi = 10 Pi. Therefore k=10.

Hope that helps.

 

[immie.rose]

Can someone PLS help me with part (ii) of the following questions?!

( 'the least value' part here specifically, pls.)

 

[sitooon]

Can someone PLS help me with part (ii) of the following questions?!

( 'the least value' part here specifically, pls.)
View attachment 38302


View attachment 38303

for first question i drew the argand diagram but not able to find least value ...
second question attached

 

[Thought blocker]

part b)

 

[ZaqZainab]

part b)

 

[Thought blocker]

Woops! Silly mistakes

 

[MiniSacBall]

A particle moves with constant acceleration along a straight line passing through the points A, B and C with speeds 2m/s, 5m/s and 8m/s respectively.
Show that the ratio between the distances AB and BC is 7:13. ?

 

[Thought blocker]

A particle moves with constant acceleration along a straight line passing through the points A, B and C with speeds 2m/s, 5m/s and 8m/s respectively.
Show that the ratio between the distances AB and BC is 7:13. ?

(A+B)/(B+c)
(2+5)/(5+8)
7/13

 

[wohooo]

For question # 7iii) Given: u = 1 + 2i/1-3i
Taking argument on both sides we have; arg(u)=arg(1 + 2i/1-3i)
or,arg(u)=arg(1+2i)-arg(1-3i)
[From 7i: arg(u)=tan-1(-.5/.5)--->3pi/4] or, 3pi/4=tan-1(2)-tan-1(-3)
Therefore, 3pi/4=tan-1(2)+tan-1(3) shown

How about no 10.iii

 

[Rahma Abdelrahman]

Can someone please tell me how to do May/June 2010 P31 Q9?
QP: http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s10_qp_31.pdf
MS: http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s10_ms_31.pdf

 

[Spectator]

 

[ZaqZainab]

View attachment 38367

 

[Spectator]

View attachment 38370

Have you skipped any of the steps ?

 

[ZaqZainab]

Have you skipped any of the steps ?

yes the simplifying do you want me to those too?

 

[Spectator]

yes the simplifying do you want me to those too?

yes please

 

[ZaqZainab]

yes please

Here
And yeah if you don't understand anything let me know

 

[Spectator]

ty, I got all things