Mathematics: Post your doubts here!

[ZaqZainab]

did u guys have addmaths?

nope

 

[ZaqZainab]

psychiatrist HOPE YOU CAN READ THE SOLUTIONS
ZaqZainab help me and him/her about the questions I had not attempt.
Question 11 part ii) ----> Like this 4-3sinx graph plot it

which paper

 

[princeali97]

came in my exam

Kewllzzz!

 

[Thought blocker]

which paper

summer 2010 variant 2 Pure math 1

 

[Serenia]

Hello!

I am sitting the P1 paper this session and I have a doubt in this exam. It is on question 4.ii).
I could solve the previous 4.i), but this one I don't understand why that is the answer on the mark scheme.

In attachements I am sending the question paper and the mark scheme.

Thank you to anyone that can help me.

 

[ZaqZainab]

summer 2010 variant 2 Pure math 1

the amplitude would be -3 and the y intercept would be 4

 

[Thought blocker]

the amplitude would be -3 and the y intercept would be 4

Ikr, but the questions in my solution, which I had not attempt. Check th
ose too

 

[Rutzaba]

lol its from nov 2013 cause i just solved this question heres goes the logic:
the differential of the function in denominator is ( 12y^3) it is present in the numerator only 4 is missing so multiply/divide by four forming:
1/4 (ln(4y^3+1) )+c

how to integrate 3y^2/4y^3+1
is it by substituition ?
how do i know which method of integration i should use? really confusing at times

http://www.examsolutions.net/maths-...egration/methods/fdash(x)overf(x)/formula.gif

 

[ZaqZainab]

Ikr, but the questions in my solution, which I had not attempt. Check th
ose too

i did'nt get what you are saying

 

[Rutzaba]

*facepalm*!!!
Jazkallahu khair!

waiyaka

 

[ZaqZainab]

Hello!

I am sitting the P1 paper this session and I have a doubt in this exam. It is on question 4.ii).
I could solve the previous 4.i), but this one I don't understand why that is the answer on the mark scheme.

In attachements I am sending the question paper and the mark scheme.

Thank you to anyone that can help me.

you know the x values
4 sin2x + 8 cos x − 7 = 0
x=60 and 300 (from (i)
in (ii) x=(1/2 tetha)
60=(1/2)tetha
and 300=(1/2) tetha
now we have tetha = 600,300
but the range they have given does not include 600 so tetha = 300

 

[Rutzaba]

can anyone solve this one? :/ im confused
http://maxpapers.com/wp-content/uploads/2012/11/9709_w13_qp_1.pdf
component 3 q8(iii)

denote the second term as b...

 

[jrahmed]

can anyone help me with may/june 2012 p33 ques 5 and 6

 

[Thought blocker]

i did'nt get what you are saying

Solve question 9 from the same paper, I was unable to do that

 

[Rutzaba]

can anyone help me with may/june 2012 p33 ques 5 and 6

Solve question 9 from the same paper, I was unable to do that

link?

 

[ZaqZainab]

Solve question 9 from the same paper, I was unable to do that

me kinda busy so i will just explain real quick
find coordinates of A and B by
7-(2x)=(x-2)^2
A(-1,9) B(3,1)
Area of shaded region = Area under the line - area under the curve
area under the line integrate (7-2x) with limits -1 and 3 you will get(7x-x^2) limits -1 and 3 answer is 20
are under the curve integrate (x-2)^2 with limits -1 and 3 you will get ((x-2)^3)/3 limits -1 and 3 answer is 28/3
Area of shaded region= 20-(28/3) =32/3=10.67

 

[Thought blocker]

link?

Link I dont have, I am on from nokia 5233, speed sucks. Paper is summer 2010_variant 12

 

[Rutzaba]

Link I dont have, I am on from nokia 5233, speed sucks. Paper is summer 2010_variant 12

dint u get zaqzainabs explanation?

 

[Thought blocker]

dint u get zaqzainabs explanation?

what after getting A and B co ordinates ?

 

[Rutzaba]

what after getting A and B co ordinates ?

dekhne do