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Mathematics: Post your doubts here!

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Can anyone solve the first question in the attached file. It's the one related to cards. help needed asap please:cry:
 

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Well, as i mentioned before, I also did it with CA x CB (and many other combinations) and got it right, so your theory fall to pieces there ^^ I just don´t get why using AC x AB or CA x BA I get the wrong answer! :(
No, you did not understand what I told you. I said, just stick to one thing. I don't know how many more ways there are to get the right answer but remembering this method is easy and it is consistent, you always get the right answer so I would recommend you to stick to just one method instead of confusing your self ;)
 
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Can anyone explain me (with diagram) how to do Q9(ii) please?

Thank you in advance!
 

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10 ii , Apply Scalar vector formula.
a *b = IaI * IbI Cos AoB

10 iii , you have OC and OA since its a parallelogram than OA=BC and OC =AB so
calculate the magnitude of OA and OC and add it and multiply by 2 that will calculate the perimenter


Q1 . Apply Tr+1 = nCr (a)^ n-r * (b)^r

Q2 apply chain rule . " y y x upon t, x , t

Q3 Simply sketch a rough .. Draw x and y axis and table method. e.g at x=1 , x=2 etc and plot it.. not to be accurate but precise as it says "sketch"
and its last part.. Integrate "Formula is V= Pie ∫ (y^2) dx . Just enter the sketch wali equation and enter in this formula. Integrate it like use to and give answer in Pie as said in question
 
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Help.

Part 2 only. guide me how to simplify it. dont take out the angle..Just do it till the basic angle.
Written will be most preferred.

6428238871.png


Suchal Riaz
AbbbbY
 
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Help.

Part 2 only. guide me how to simplify it. dont take out the angle..Just do it till the basic angle.
Written will be most preferred.

6428238871.png


Suchal Riaz
AbbbbY

1/(sin^2A - cos^2A) = 3
1 = 3sin^2A - 3cos^2A
sin^2A + cos^2A = 3 sin^2A - 3cos^2A
4cos^2A = 2sin^A
tan^2A = 2
Solve for A. Remember to get both, the + and the - values.
Let me know if this doesn't make sense to you.
 
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I´ll post this once, once, again...

I´ve got a question and would appreciate some help.

For Q9(i), if you are trying to find the normal to the plane using vector product, why if you do AC x AB or CA x BA you get a wrong answer, but if you use any other two vectors, you get the correct normal to the plane? The only difference for the normal to the plane I get using AC x AB or CA x BA is a minus sign for the k coordinate, instead of a positive one (just asking this in the case someone knows an explanation for it).

I would also like if someone could clarify me how to use vector product correctly, ie. what requisites should the vectors you are going to use for vector product have?

ALSO, how do you do Q9(ii).

Thank you in advance.
 

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I´ll post this once, once, again...

I´ve got a question and would appreciate some help.

For Q9(i), if you are trying to find the normal to the plane using vector product, why if you do AC x AB or CA x BA you get a wrong answer, but if you use any other two vectors, you get the correct normal to the plane? The only difference for the normal to the plane I get using AC x AB or CA x BA is a minus sign for the k coordinate, instead of a positive one (just asking this in the case someone knows an explanation for it).

I would also like if someone could clarify me how to use vector product correctly, ie. what requisites should the vectors you are going to use for vector product have?

ALSO, how do you do Q9(ii).

Thank you in advance.
yar A cross B
and b cross A are both acceptable...
 
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