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No, you did not understand what I told you. I said, just stick to one thing. I don't know how many more ways there are to get the right answer but remembering this method is easy and it is consistent, you always get the right answer so I would recommend you to stick to just one method instead of confusing your selfWell, as i mentioned before, I also did it with CA x CB (and many other combinations) and got it right, so your theory fall to pieces there ^^ I just don´t get why using AC x AB or CA x BA I get the wrong answer!
Got it!! thankkss rutzaba!!! :')
Just gave it a try,are the following answers correct?Can anyone solve the first question in the attached file. It's the one related to cards. help needed asap please
http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_w03_qp_6.pdfJust gave it a try,are the following answers correct?
I)0.774
II)0.204
III)0.041(wrong definitely)
Can someone help please, no one is replying
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s10_qp_11.pdf
Question 10 ii , iii
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s11_qp_11.pdf
Q1,2,3 . I don't get any
PLease help
Awesome!
Help.
Part 2 only. guide me how to simplify it. dont take out the angle..Just do it till the basic angle.
Written will be most preferred.
Suchal Riaz
AbbbbY
thankyou. Understood!1/(sin^2A - cos^2A) = 3
1 = 3sin^2A - 3cos^2A
sin^2A + cos^2A = 3 sin^2A - 3cos^2A
4cos^2A = 2sin^A
tan^2A = 2
Solve for A. Remember to get both, the + and the - values.
Let me know if this doesn't make sense to you.
im in uni swthrtGot it!! thankkss rutzaba!!! :')
May u get STRAIGHT A*s and even distinctions!! )
1/(sin^2A - cos^2A) = 3
1 = 3sin^2A - 3cos^2A
.
oc-oa
Part 2.
I am getting 1 +2P^2 and back in Ms its 1+4P^2 + q^2
Part 2.
I am getting 1 +2P^2 and back in Ms its 1+4P^2 + q^2
yar A cross BI´ll post this once, once, again...
I´ve got a question and would appreciate some help.
For Q9(i), if you are trying to find the normal to the plane using vector product, why if you do AC x AB or CA x BA you get a wrong answer, but if you use any other two vectors, you get the correct normal to the plane? The only difference for the normal to the plane I get using AC x AB or CA x BA is a minus sign for the k coordinate, instead of a positive one (just asking this in the case someone knows an explanation for it).
I would also like if someone could clarify me how to use vector product correctly, ie. what requisites should the vectors you are going to use for vector product have?
ALSO, how do you do Q9(ii).
Thank you in advance.
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