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ii)
from part i) f(g) = 2x^2- 3 and g(f) = 4x^2 + 4x - 1
so for this part put a instead of x, and solve the equation , you get a as -1
iii)
given g(b) = b ; b^2 - b - 2 = 0 ; you get b as 2 and -1 ; and b is not equal to a hence b is 2