Mathematics: Post your doubts here!

[kitkat <3 :P]

kit kat thank you :'')

lol no prob

 

[IGCSE13]

https://www.xtremepapers.com/commun...s-s1-post-your-doubts-here.33781/#post-787629

 

[Tanvir Azad]

put DY/DX =0 then solve this and curve equation simultaneously

ok... i got it.. Thanks

 

[Heyyy]

let u^2 =x
that means dx/du =2u that means differentiating u^2 woth respect to u
dx= 2u du
next thing is to change limits...
if u^2 =x
when upper limit of x=p^2 then replace x with p^2
u^2 = p^2
new upper limit =p
and since o will remain o
the new limits are p and o

then u have to integrate cos of root of u^2
root will cut the sqr u will get
integral of cos u dx
now look at the third line of this solution u will find dx= 2u du
integral of cosu 2u du for the limit p and 0
integrating by parts
u= 2u dv= cos u
u'=2 v= sinu
2u sin u- integral of 2sin u
2usinu -( -2cosu)
2usinu + 2cos u... apply limits p and 0
2p sinp + 2cosp - ( o +2 cos0)
2psin p +2cosp -2(1)=1 as this is also equal to the area of the shaded region...
2p sinp= 3-2cosp
sinp= 3-2cosp / 2p

Thanks A lot!!!
I wasn't integrating it by parts :/
Anyways,thanks again

 

[A star]

guys is 2012 and 2011 all variants enough to know how much is your prep :S

 

[Rutzaba]

guys is 2012 and 2011 all variants enough to know how much is your prep :S

wont u be solving all the pprs?

 

[A star]

wont u be solving all the pprs?

i already have solved 2002 -2009 before 1st of may

 

[ZaqZainab]

i already have solved 2002 -2009 before 1st of may

Hi-5

 

[Rutzaba]

hmm phir pych kia rhe ho?

 

[A star]

hmm phir pych kia rhe ho?

yar i said i solved them i didnt say succesfully to many errors and problems

 

[Rutzaba]

Part 5 ii again Rutzaba (sorry for tagging, but due to quick response I am really really really glad)
Yess More prayers coming!View attachment 42627

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s12_qp_31.pdf

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s12_ms_31.pdf

Can anyone explain to me wat the ms is saying for Q10 part iv??! >.<
these cie people cud try making a marking scheme when they are not drunk for a change >_<

this doesnt make any sense

I got the answer 0.906 but all these other values given in the ms seem to b mumbo jumbo to me

hogaye ye wale or shall i do em?

 

[Rutzaba]

Thanks A lot!!!
I wasn't integrating it by parts :/
Anyways,thanks again

pray in return

 

[daredevil]

hogaye ye wale or shall i do em?

ummm do it ^__^
thanks in advance ^__^

 

[Ayeshak93]

Q9 b part is giving me a headache...Please help!

 

[Lostsoul]

Kardo pls

 

[saqib.tariq]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_S08_qp_01.pdf

question number 8 all ?????

 

[A*(a*)]

hmm phir pych kia rhe ho?

Can you please solve the (ii)b ? Its N10/33 Q8

 

[A*(a*)]

pray in return

And also,

its the same year, Q10. I cant solve (ii)b

 

[saqib.tariq]

how the gradient of AC is -1/2 plz help

 

[Ayeshak93]

Q. 10 part 2