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Mathematics: Post your doubts here!

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Guys i want to ask you how much time does it usually take to do A2 maths P3 and S1? Can i do it in 5 months with past papers practice that ensures me A grade?
what were your AS grades?
talking about practice i believe S1 needs more practice while for pure you need clear up the concepts real good. But do practice for both the papers coming to which past years papers more the better but if you don't have much time you should surely do the latest one try to get the patter there are high chances of same format of paper.
 
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ATTENTION A LEVEL STUDENTS [S1 Students]

Video Solutions For June 2009 S1

Playlist :: https://www.youtube.com/playlist?list=PLOueJSLH9a-Ngx2v4rR3vQ_FZIoSzqzie

By 16 September 2014; there will be a DVD Video Solutions for S1; June 2009 to November 2013, detailed explanation and working of these past exam questions for only Rs 350. Those interested can inbox me or give me a call on 5712 5974.

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Guys i want to ask you how much time does it usually take to do A2 maths P3 and S1? Can i do it in 5 months with past papers practice that ensures me A grade?
 
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Guys i want to ask you how much time does it usually take to do A2 maths P3 and S1? Can i do it in 5 months with past papers practice that ensures me A grade?
if u concentrate on p1 and try to maximise your mark in that paper than you can do the maximum that you can in s1 u will surely get good results.....the paper weightage for p1 is higher than that for s1
 
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what were your AS grades?
talking about practice i believe S1 needs more practice while for pure you need clear up the concepts real good. But do practice for both the papers coming to which past years papers more the better but if you don't have much time you should surely do the latest one try to get the patter there are high chances of same format of paper.

P1: A M1: A
 
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how to prove (sinx+cosx)(1-sinxcosx) equals to sin^3x+cos^3x?
I will twist it to : (sin^3x+cos^3x)/(sinx+cosx) = 1-sinxcosx. Its the same question, just a minor twist, do it yourself the original question, here it is :¬
=> (sin^3x+cos^3x)/(sinx+cosx)
[Just use the a^3+b^3 formula]
=> [(sinx+cosx)(sin^2x-sinx.cosx+cos^2x)] / (sinx+cosx)
[The sinx+cosx from numerator and denominator cancels out]
=> sin^2x-sinx.cosx+cos^2x
=> 1-sinx.cosx [because sin^2x+cos^2x = 1]
=> RHS...Proved
 
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I will twist it to : (sin^3x+cos^3x)/(sinx+cosx) = 1-sinxcosx. Its the same question, just a minor twist, do it yourself the original question, here it is :¬
=> (sin^3x+cos^3x)/(sinx+cosx)
[Just use the a^3+b^3 formula]
=> [(sinx+cosx)(sin^2x-sinx.cosx+cos^2x)] / (sinx+cosx)
[The sinx+cosx from numerator and denominator cancels out]
=> sin^2x-sinx.cosx+cos^2x
=> 1-sinx.cosx [because sin^2x+cos^2x = 1]
=> RHS...Proved
thanks. do you know how to quickly find the range of a function like 5-3sinx? or something similar. my teacher tells us to sketch but i think id miss a point
 
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