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use 1/2 * BC * OAView attachment 51292
The main problem I do not understand is that how do we calculate the area of the triangle ABC while it is not making any triangle??
Please help me out of this confusion![]()
Just got it..Thanks Amigouse 1/2 * BC * OA
5)i) mgh = 1/2mv^2PLZ someone help me with these questions !!
For question 9:
part 1)
w=x+iy
w*=x-iy
Substitue this in the equation
equate real and imaginary parts
get value of x= 2(2)^.5 and y=-2
part 2)
all drawing of circle and lines and distance :S. If you cannot calculate it,then reply below![]()
n of q = (1,b,c)Q10(ii) Please anyone explain me
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s13_qp_32.pdf
It's used to check how many real roots a quadratic equation has.When is equation
b² - 4ac
used?
This is known as the discriminent.When is equation
b² - 4ac
used?
Sorry to InterruptFor questions 5:
First differentiate the equation in terms of x
replace dy/dx as 0
You will get the equation: 3x^2+y^2-6ax=0
From original equation make y the subject
Replace in the equation above.
You will get the value of x= (3a)^1/2
1/r + 1/(r+1) + 1/(1-r)....Is this right ans.. Let me know
No, the answer in the scheme doesn't work if x > .54HELP NEEDED
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s12_ms_32.pdf
QUESTION 5
MY ANSWER IS Y=X-0.5LN3
is it the same thing as the answer in the marking scheme??
1/r(r+1)(r-1) ≡ A/r + B/(r+1) + C/(r-1)
cosAOP = cosBOPcan someone help me out in a question?
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_ms_31.pdf
question 7
find y in terms of x in original equation and replace it.Sorry to Interrupt.. How do we elminate y2 in the equation??
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