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use 1/2 * BC * OAView attachment 51292
The main problem I do not understand is that how do we calculate the area of the triangle ABC while it is not making any triangle??
Please help me out of this confusion
Just got it..Thanks Amigouse 1/2 * BC * OA
5)i) mgh = 1/2mv^2PLZ someone help me with these questions !!
For question 9:
part 1)
w=x+iy
w*=x-iy
Substitue this in the equation
equate real and imaginary parts
get value of x= 2(2)^.5 and y=-2
part 2)
all drawing of circle and lines and distance :S. If you cannot calculate it,then reply below
n of q = (1,b,c)Q10(ii) Please anyone explain me
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s13_qp_32.pdf
It's used to check how many real roots a quadratic equation has.When is equation
b² - 4ac
used?
This is known as the discriminent.When is equation
b² - 4ac
used?
Sorry to Interrupt .. How do we elminate y2 in the equation??For questions 5:
First differentiate the equation in terms of x
replace dy/dx as 0
You will get the equation: 3x^2+y^2-6ax=0
From original equation make y the subject
Replace in the equation above.
You will get the value of x= (3a)^1/2
1/r + 1/(r+1) + 1/(1-r)....Is this right ans.. Let me know
No, the answer in the scheme doesn't work if x > .54HELP NEEDED
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s12_ms_32.pdf
QUESTION 5
MY ANSWER IS Y=X-0.5LN3
is it the same thing as the answer in the marking scheme??
1/r(r+1)(r-1) ≡ A/r + B/(r+1) + C/(r-1)
cosAOP = cosBOPcan someone help me out in a question?
http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w11_ms_31.pdf
question 7
find y in terms of x in original equation and replace it.Sorry to Interrupt .. How do we elminate y2 in the equation??
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