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Mathematics: Post your doubts here!

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Here you go , if I have any mistake tell me =)
For part three you just have to sub in any root from the two roots you got in part 1 in z^6 and expand and simplify, you will reach -64
Thanku,so basically its expansion of any of the conjugates??
 
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It's the expansion of any of the roots and simplifying it
please explain how to eliminate y from last step to get answer for x in terms of a

11212216_10202852870161720_1031464285_n.jpg
 
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i) The function is made up of 2 parts: Curve + Straight line. The domain is given for both parts and the resulting graph is said to be of f(x). So if we look at the graph we know the max and min x-values. They are given in the domains in the question. Max x-value is 4 and Min x-value is -1.
Now the top part is the curve so we put x-value 4 in the curve equation to get the max y-value and the x-value -1 in the straight line equation to get the minimum y-value and that is the range.
56T6MX0.jpg


ii) I hope you can find the inverses. They are easy. Here is the graph:
Dotted lines are from the inverse functions.
0RiP0Bf.jpg
 
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Need help ASAP
M/J 2014 P12 Q#2 (Binomial Part)
How do we DO these type of questions???
 
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Hey guys, can anyone help me out with Q3 (i)? Thank you! :)
 

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i) The function is made up of 2 parts: Curve + Straight line. The domain is given for both parts and the resulting graph is said to be of f(x). So if we look at the graph we know the max and min x-values. They are given in the domains in the question. Max x-value is 4 and Min x-value is -1.
Now the top part is the curve so we put x-value 4 in the curve equation to get the max y-value and the x-value -1 in the straight line equation to get the minimum y-value and that is the range.
56T6MX0.jpg


ii) I hope you can find the inverses. They are easy. Here is the graph:
Dotted lines are from the inverse functions.
0RiP0Bf.jpg
Thanks A LOT >>> really helpful !
 
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Hey.
I m getting really tensed forr tomorrow's Math exam.
Has anyone been done with AS maths today?
 
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how to know if a function will have inverse or not ..and how to find minimum value for it to be inverse
 
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