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Mathematics: Post your doubts here!

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Hey Guys, can someone please solve 6 (ii)?
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Hey Guys, can someone please solve 6 (ii)?
Untitled.png

there are 2 cases of constant acceleration.
Before reaching the liquid:
a = 10 s = 5 u = o v = ? t = ?
use constant acceleration formulas to find v and t
v = 10, t = 1

Inside the liquid:
a = 5.5 s = 4 u = 10 (v of previous) v = ? t = ?
again use constant acceleration formulas
v = 12, t = 0.36

For the sketch, make a straight line from the origin to (1, 10). This is for the part before the liquid
Then make a line of less gradient from (1,10) to (1.36, 12) for the part inside the liquid.
 
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Why isn't T2 20s? My values were 10 and 30 but when I inserted value of 21 in second derivative of velocity it was giving me positive so increasing? And when I put 19 it was giving me negative so decreasing?_20150511_142356.JPG
 
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there are 2 cases of constant acceleration.
Before reaching the liquid:
a = 10 s = 5 u = o v = ? t = ?
use constant acceleration formulas to find v and t
v = 10, t = 1

Inside the liquid:
a = 5.5 s = 4 u = 10 (v of previous) v = ? t = ?
again use constant acceleration formulas
v = 12, t = 0.36

For the sketch, make a straight line from the origin to (1, 10). This is for the part before the liquid
Then make a line of less gradient from (1,10) to (1.36, 12) for the part inside the liquid.
Aren't we supposed to make the graph in the negative section? because it is going downwards isn't it?
 
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