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Mathematics: Post your doubts here!

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http://onlineexamhelp.com/wp-content/uploads/2012/05/9709_s07_qp_3.pdf

I need help for question 9(ii). I don't get what the examiner report says about finding unit vector k?? :cry:
To find the acute angle, you need to find the normals of the two planes and find the angle between them, from i) we know the normal of the plane ABC, but plane OAB has a normal of (0,0,1) because it's normal is perfectly vertical, it's direction is 1k
Then scalar product: Costheta= (N1.N2)/(|N1||N2|)
 
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If the equation of a curve= 0 the will the equation of the tangent also equal 0?? CAN SOMEONE PLS ANSWER THIS
 
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If the equation of a curve= 0 the will the equation of the tangent also equal 0?? CAN SOMEONE PLS ANSWER THIS
If you equate the equation of the curve to zero you get the solution of the curve
and if you equate the derivate of the equation to zero, you get the stationary point.
If you have a point on the curve, you can use the coordinates of that point and the gradient of the curve at that point to find the equation of the tangent to the curve at that point.
 
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If you equate the equation of the curve to zero you get the solution of the curve
and if you equate the derivate of the equation to zero, you get the stationary point.
If you have a point on the curve, you can use the coordinates of that point and the gradient of the curve at that point to find the equation of the tangent to the curve at that point.
Yea I know.. But will the equation of the tangent also be equal to 0? I saw some qs in which they did that
 
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