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Mathematics: Post your doubts here!

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Mass = 1100
Fd = 1800
Fr = 700N
Distance = x
Speed = v
i) K.E = 1/2(1100)v^2 = 550v^2
P.E = (1100)(10)(160) = 1760000 Now we have to find it in terms of x which is distance. So it will become 1760000/1760 = 1000x

kv^2 = x
1800x = 700x+ 550v^2+ 1000x
^This is the WD equation. I just substituted everything in terms of x and v
Solve it further you will get
100x = 550v^2
x = 550/100v^2
x = 5.5v^2
Hence k = 5.5 Ans.

ii) 5.5v^2 = 1760
v^2 = 320

1800(x-1760) = 700(x-1760)+ 550(v^2-320) [we subtracted 320 because it was our initial velocity and so to find gain in K.E we already have v^2(initial velocity)
1800x-3168000 = 700x - 1232000+ 550v^2 - 176000
1800x-700-3168000 = -1408000+ 550v^2
1100x-3168000+ 1408000 = 550v^2
1100x+ 1760000 = 550v^2
(1100x+ 176000)/550 = v^2
v^2 = 2x - 3200 (shown)


thnx a lot : )
 
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take lcm
dh/dt = (100-h^2)/20h^2
(20h^2/(100-h^2)) dh = dt
Use result from part 2.
-20 + 2000/(10-h)(10+h) dh = dt
use partial fractions
-20 + 100/(10-h) + 100/(10+h) dh = dt
then integrate
Did you try partial fractions?
Thaks a lot
Yes i did but my C is zero just wanted to confirm because in ms there's no correct answer given.

Btw in 2 nd part can we just say assume h=1 anwers are 2/100 and 2/99 so since the answers are close enough hence we can say that they are eqivalent
 
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Thaks a lot
Yes i did but my C is zero just wanted to confirm because in ms there's no correct answer given.

Btw in 2 nd part can we just say assume h=1 anwers are 2/100 and 2/99 so since the answers are close enough hence we can say that they are eqivalent
Both of those things are in the examiner report.
 
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can u plz suggest a good book for further math
Further Pure Mathematics by Brian and Mark Gaulter
A Concise Course in Advanced Level Statistics by Crawshaw and Chambers
Mechanics for A Level by Bostock and Chandler

They don't cover all the topics, but you can find the majority of them in these books.
 
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Further Pure Mathematics by Brian and Mark Gaulter
A Concise Course in Advanced Level Statistics by Crawshaw and Chambers
Mechanics for A Level by Bostock and Chandler

They don't cover all the topics, but you can find the majority of them in these books.
thnx
 
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consider points A and C, u have...
time = 6s
displacement = 60m
initial velocity = 4 m/s

use s = ut + 1/2 at^2, and u get a = 2 m/s^2

now that u have acceleration,
consider points A and B,
time = 3s
initial velocity = 4 m/s
acc = 2

use again s = ut + 1/2 at^2
s = 21 m
Thanx bro..!
 
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https://mathway.com/
:)

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