When the car is accelerating:
s = (v²-u²)/2a
= (15²-0)/2(5) = 22.5 m
time taken for acceleration
t = (v-u)/a
= (15-0)/5 = 3 s
When the car is speeding uniformly:
s = velocity x time = 15 x 10 min x 60s = 9000m
When the car is decelertating:
s = (v²-u²)/2a
= (0-15²)/2(-8) = 14.1 m
time taken for decelartion
t = (v-u)/a
= (0-15)/(-8) = 1.9 s
Total journey time = 3 + (10x60) + 1.9 = 604.9s
s = (v²-u²)/2a
= (15²-0)/2(5) = 22.5 m
time taken for acceleration
t = (v-u)/a
= (15-0)/5 = 3 s
When the car is speeding uniformly:
s = velocity x time = 15 x 10 min x 60s = 9000m
When the car is decelertating:
s = (v²-u²)/2a
= (0-15²)/2(-8) = 14.1 m
time taken for decelartion
t = (v-u)/a
= (0-15)/(-8) = 1.9 s
Total journey time = 3 + (10x60) + 1.9 = 604.9s