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Mathematics: Post your doubts here!

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solving left hand side,
open up the bracket which gives u... cos^2x+6sinxcosx+9sin^2x

use the identity sin2x=2sinxcosx
so u need to get 6sinxcosx so multilpy it by 3... 3sin2x=6cosxsinx

equation becomes cos^2x+3sin2x+9sin^2x
so simplifying it further cos^2x+3sin2x+9(1-cos^2x)
cos^2x+3sin2x+9-9cos^2x
-8cos^2x+9+3sin2x

if u look at 5-4cos2x....its basically the same as -8cos^2x+9 when u simplify it so replace it with that...
thus 5-4cos2x+3sin2x proven

u need to show them how u converted the 5-4cos2x into -8cos^2x+9
 
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upload_2016-2-9_19-2-4.png
Can someone please sketch the diagram for (b)(i) please?
So I know the first one is a circle with centre 2+i and radius 1
Now the second equation i solved
(x+iy+i)<(x+iy-2)
this gives
y>2x-1.5
So i drew a line like so...
Is it correct as the ms says this :
upload_2016-2-9_19-4-23.png
upload_2016-2-9_19-7-23.png
 
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Can you please show how to obtain the answers using trigonometry on the diagram ?
upload_2016-2-12_13-36-52.png
Magnifying the triangle we can find the angles and use the sine rule
The argument of blue line is given in question as pi/6
red is y=x hence the argument is pi/4
Knowing these 2 angles you can find the other angles
We know the blue line cuts the imaginary axis at 2 (when we solved the equation above) so the length will be 2
Now apply the sine rule as x = [2/sin(pi/2)] * [sin(2pi/3)]
 
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