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lol good. Now you know it's not just as simple as saying 'binomial expansion'Please help asap, I have test in my tuition tomorrow early morning. I remember![]()
All the best!
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lol good. Now you know it's not just as simple as saying 'binomial expansion'Please help asap, I have test in my tuition tomorrow early morning. I remember![]()
Same method here again bruh ... It will be useful if you can remember this formula (it's not given in the formula sheet) :
You saved me, I also did silly mistake..Same method here again bruh ... It will be useful if you can remember this formula (it's not given in the formula sheet) :
(1+x)^-1 = 1 - (x) + (x)^2 - (x)^3
Saves a lot of time and effort than the original one, and it's what I've used in solving these problems.
![]()
Messy, but understandable right?
Savior B|You saved me, I also did silly mistake..
I hope I will score full marks, only this was my problem, rest other is as easy as piece of a cake. Moreover its as easy to say as binomial expansion, its just one silly mistakes can cost u many marks.. xD
I will tell u my marks afternoon.![]()
Savior B|
piece of cake? really bro? cool ... i make mistakes in vectors and stuff ... prolly cuz i've only done 2 to 3 papers so far
Yeah sure do![]()
Vectors are really easy to solve, just jot down all the concepts in one piece of a paper, and revise it everytime u come through that paper. And then see where u are making the mistakes in vector questions and work on it. Yes I also use to do mistakes till my 3 to 5 papers. But now, I have made my weak points to be strong points.Savior B|
piece of cake? really bro? cool ... i make mistakes in vectors and stuff ... prolly cuz i've only done 2 to 3 papers so far
Yeah sure do![]()
So yeah ... not as easy as just saying 'binomial expansion'![]()
Paper was really damn easy, I think I made a mistake in binomial expansion xD That's it. As expected...
completed paper in just 45 mins..
This was the question, can u please show me the working of it?![]()
uhuh ... thanks man! will try to do but imma be lazy :/Vectors are really easy to solve, just jot down all the concepts in one piece of a paper, and revise it everytime u come through that paper. And then see where u are making the mistakes in vector questions and work on it. Yes I also use to do mistakes till my 3 to 5 papers. But now, I have made my weak points to be strong points.Similarly do this with any conceptual questions. ^_^
I think this is O level stuff? Not able to remember how to do this ... you can maybe post it in the IG threads here?Repost: can someone help me with the last two problems? its a little urgent, would be much appreciatedView attachment 59359
Sorry for the late reply! I believe you answered this?This was the same type of question you had asked me to do binomial expansion in remember?
Well, I can't believe I'm getting it wrong again! So frustrating.
nehaoscar please once again?![]()
YeahSo yeah ... not as easy as just saying 'binomial expansion'
The 2nd part?
uhuh ... thanks man! will try to do but imma be lazy :/
yea that one done ... but now plz do this oneSorry for the late reply! I believe you answered this?
No silly mistakes this time!![]()
![]()
The Sarcastic Retardyea that one done ... but now plz do this one![]()
Retard bruh ... I ain't got the energy to try that and electric fields together so.![]()
let <ADE = aJust the last two , thanks a lot !View attachment 59312
thanks a lot! and the last problem if it isn't too much trouble....let <ADE = a
then,
<ADE = <DCA = a
also,
<DCA = <DBA = a (<s subtended by arc at circumference are equal)
<ADB = 90 (angle subtended by diameter at circumference is 90)
<ADE + <EDB = <ADB
a + <EDB = 90
<EDB = 90 - a
now consider triangle DEB,
the sum of interior angles in a triangle is 180, so
<DEB + <DBA + <EDB = 180
<DEB + a + 90 - a = 180
<DEB = 90 (proved)
(ii) <ACB = 90 (angle subtended by diameter at circumference is 90)
in a cyclic quadrilateral, the sum of two angles facing each other is 180.
So,
<ACB = <FCB
<FCB + <FEB = 90+90 = 180
in a quadrilateral, the sum of all interior angles is 360, so
<FEB + <FCB + <CFE + <EBC = 360
180 + <CFE + <EBC = 360 ( <FCB + <FEB = 180 )
<CFE + <EBC = 180
Hence shown that FEBC is a cyclic quadrilateral.
Thanks. ^_^
need help on this ! thanks part (ii)
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