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Mathematics: Post your doubts here!

qwertypoiu

qwertypoiu

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farhan141 said:
I have never seen this method before.. Can it be done by diagram?
Click to expand...
Yes you can make diagrams and solve by coordinate geometry as well.
The first condition specifies a set of points that make a slope of 1/sqrt(3). It also has y intercept of 2. So the equation will be y = 1/sqrt(3) *x + 2.
The second condition specifies a set of points that are equidistant from (0,3) and (3,0). The line will be a perpendicular bisector of the line that joins these two points. You'll find that this equation is the line y=x

By solving these two equations simultaneously, you can find the real and imaginary part of P and proceed to convert the complex number into the required form.

A note about the other method I sent as an attachment, where I wrote "tan" it should have been tan^-1 (INVERSE TAN)
 
F

farhan141

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qwertypoiu said:
Yes you can make diagrams and solve by coordinate geometry as well.
The first condition specifies a set of points that make a slope of 1/sqrt(3). It also has y intercept of 2. So the equation will be y = 1/sqrt(3) *x + 2.
The second condition specifies a set of points that are equidistant from (0,3) and (3,0). The line will be a perpendicular bisector of the line that joins these two points. You'll find that this equation is the line y=x

By solving these two equations simultaneously, you can find the real and imaginary part of P and proceed to convert the complex number into the required form.

A note about the other method I sent as an attachment, where I wrote "tan" it should have been tan^-1 (INVERSE TAN)
Click to expand...

Ok I'll try it later then let u know if I have any questions :).
 
Rizwan Javed

Rizwan Javed

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Rifat Fawzia said:
Assalamu alaikum :)
Do u have P1 & P4 all varients of oct-nov 2015 solved papers???
Click to expand...
Rifat Fawzia said:
Assalamu alaikum :)
Do u have P1 & P4 all varients of oct-nov 2015 solved papers???
Click to expand...
pdf.gif
2015_May_June_Paper_11.pdf
pdf.gif
2015_May_June_Paper_12.pdf
pdf.gif
2015_May_June_Paper_13.pdf
P1 papers :p
 
The Sarcastic Retard

The Sarcastic Retard

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Rizwan Javed said:
Don't know for sure, but may be it means that Population follows a normal distribution :p
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I had a question in my stats-2 paper today, why is sample mean normally distributed. The real answer was coz population is normal, but I wrote that coz sample has continuous data or unbiased data.. Will this be give correct?
Thanks.
 
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