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Mathematics: Post your doubts here!

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farhan141

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qwertypoiu said:
They said parallel to x axis. (1,0,0) is the simplest vector that goes in the direction of x axis. It's a unit vector as well so that's why I chose it. You can choose any vector in the form (s, 0,0), and it will be parallel to x axis.
Click to expand...

so if its parallel to y axis then its 0,s,0?
 
qwertypoiu

qwertypoiu

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farhan141 said:
I have never seen this method before.. Can it be done by diagram?
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Yes you can make diagrams and solve by coordinate geometry as well.
The first condition specifies a set of points that make a slope of 1/sqrt(3). It also has y intercept of 2. So the equation will be y = 1/sqrt(3) *x + 2.
The second condition specifies a set of points that are equidistant from (0,3) and (3,0). The line will be a perpendicular bisector of the line that joins these two points. You'll find that this equation is the line y=x

By solving these two equations simultaneously, you can find the real and imaginary part of P and proceed to convert the complex number into the required form.

A note about the other method I sent as an attachment, where I wrote "tan" it should have been tan^-1 (INVERSE TAN)
 
F

farhan141

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qwertypoiu said:
Yes you can make diagrams and solve by coordinate geometry as well.
The first condition specifies a set of points that make a slope of 1/sqrt(3). It also has y intercept of 2. So the equation will be y = 1/sqrt(3) *x + 2.
The second condition specifies a set of points that are equidistant from (0,3) and (3,0). The line will be a perpendicular bisector of the line that joins these two points. You'll find that this equation is the line y=x

By solving these two equations simultaneously, you can find the real and imaginary part of P and proceed to convert the complex number into the required form.

A note about the other method I sent as an attachment, where I wrote "tan" it should have been tan^-1 (INVERSE TAN)
Click to expand...

Ok I'll try it later then let u know if I have any questions :).
 
Rizwan Javed

Rizwan Javed

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Rifat Fawzia said:
Assalamu alaikum :)
Do u have P1 & P4 all varients of oct-nov 2015 solved papers???
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Rifat Fawzia said:
Assalamu alaikum :)
Do u have P1 & P4 all varients of oct-nov 2015 solved papers???
Click to expand...
pdf.gif
2015_May_June_Paper_11.pdf
pdf.gif
2015_May_June_Paper_12.pdf
pdf.gif
2015_May_June_Paper_13.pdf
P1 papers :p
 
The Sarcastic Retard

The Sarcastic Retard

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Rizwan Javed said:
Don't know for sure, but may be it means that Population follows a normal distribution :p
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I had a question in my stats-2 paper today, why is sample mean normally distributed. The real answer was coz population is normal, but I wrote that coz sample has continuous data or unbiased data.. Will this be give correct?
Thanks.
 
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