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They asked for the work done by the driving force while travelling on the slope(which is 800 m). If you take d sin(theta), it gives you the vertical distance between the slope and the ground .For part b why dont we use d sin theta over here?
Also if resistive forces were given will we use d or d sin theta?
View attachment 60373
Yeah alright. Thank youThey asked for the work done by the driving force while travelling on the slope(which is 800 m). If you take d sin(theta), it gives you the vertical distance between the slope and the ground .
Thanks.
View attachment 60387 View attachment 60388
Why is the encircled part done in the MS? Why couldn't it simply be 0.4g-1.4=0.4a
Oh alright. Thanks.View attachment 60390
- find sin (theta) from the equation .
- using newton's second law , ( 0.4g x sin(theta)) - 1.4 = 0.4a
how do you know between 0 and π symbol curves like that?View attachment 60395
Something like this^
2nd part. View attachment 60393

http://www.intmath.com/trigonometric-graphs/1-graphs-sine-cosine-amplitude.php this could figure your doubt out.how do you know between 0 and π symbol curves like that?
im sorry for such a stupid qs
thank youhttp://www.intmath.com/trigonometric-graphs/1-graphs-sine-cosine-amplitude.php this could figure your doubt out.
And also this http://www.purplemath.com/modules/grphtrig.htm
thank you so much rizwanThe normal sine curve is like this:
View attachment 60397
But when there's a negative sign with sine, the curve is inverted like this:
View attachment 60399
I did multiply6 is in numerator and u didnt multiply it after u expanded them?
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