Mathematics: Post your doubts here!

[Copy Cat]

1st part only. Can u tell me answer of the second?

View attachment 60467

 

[qwertypoiu]

View attachment 60468

Spoiler

Edit! :
Once you have k=4/3, you can just proceed directly to tan-1(4/3) = 0.927

 

[Copy Cat]

1st part only. Can u tell me answer of the second?

View attachment 60467

Spoiler

View attachment 60469

Edit! :
Once you have k=4/3, you can just proceed directly to tan-1(4/3) = 0.927

Thanks a ton!!!!!!!!

 

[Awesome12]

Oh ok, I didn't visualize it as being the equation of the line. Thanks.

 

[farhan141]

Spoiler

View attachment 60469

Edit! :
Once you have k=4/3, you can just proceed directly to tan-1(4/3) = 0.927

Where did u disappear in last few days

 

[Copy Cat]

 

[The Sarcastic Retard]

Part (ii)

Spiceangel The Sarcastic Retard muhammadali233 farhan141 qwertypoiu Awesome12 *Le me* Akshajistari

http://bmaths.weebly.com/uploads/2/5/6/4/25647388/s1_revision_pack_4_-_probability_distributions.pdf Q13

 

[Copy Cat]

I only need the first part.
p<Z<q?

Thanks

 

[qwertypoiu]

View attachment 60470

Spoiler

 

[Fiery987]

Ohh got it! Thanks man .

How's ur prep overall? How is S1 going? What abt Physics and Chem?

60 - 70 %. Chemistry is OK. Math P3 needs some practice. I rock in Physics but I was never good in Statistics (S1 in this case) .

How about you?

 

[qwertypoiu]

View attachment 60473
I only need the first part.
p<Z<q?

Thanks

Is this the entire question? Seems like it's missing something

 

[qwertypoiu]

Where did u disappear in last few days

Just brushing on my bio man :/

 

[Copy Cat]

Spoiler

View attachment 60474

y=-x+2-----Equation of line
How did you managed to get the other co-ordinates?
(2,0) And?

Thanks is advance...........

 

[Copy Cat]

Is this the entire question? Seems like it's missing something

b(ii) part

 

[qwertypoiu]

y=-x+2-----Equation of line
How did you managed to get the other co-ordinates?
(2,0) And?

Thanks is advance...........

Consider arg(z) = 3/4*pi
This represents the set of points whose argument is 3/4*pi. In other words, this is a line which makes the angle 3/4*pi radians with the x axes (in anticlockwise direction).
By doing tan(3/4*pi), we can find the gradient of the line, which is -1. So our equation is y=-x (passes through origin)
Changing arg(z) to arg(z-2) has the effect of shifting all the points to the right by 2 units, so now our equation becomes y=-x+2

 

[qwertypoiu]

View attachment 60475
b(ii) part

So basically you have a set of points that form a circle, with centre (4,4) and radius 2.
The distance from Origin to Centre = √(4²+4²) = 5.66
p = Ans - 2 = 3.66
q = Ans + 2 = 5.66

 

[Fiery987]

So basically you have a set of points that form a circle, with centre (4,4) and radius 2.
The distance from Origin to Centre = √(4²+4²) = 5.66
p = Ans - 2 = 3.66
q = Ans + 2 = 5.66

Shouldn't it be √(6²+6²) for q and likewise for p?
And what about 'arg' part?

 

[qwertypoiu]

Shouldn't it be √(6²+6²) for q and likewise for p?
And what about 'arg' part?

The questioner didn't ask about the arg part but if you want I'll do it tomorrow

 

[Copy Cat]

Consider arg(z) = 3/4*pi
This represents the set of points whose argument is 3/4*pi. In other words, this is a line which makes the angle 3/4*pi radians with the x axes (in anticlockwise direction).
By doing tan(3/4*pi), we can find the gradient of the line, which is -1. So our equation is y=-x (passes through origin)
Changing arg(z) to arg(z-2) has the effect of shifting all the points to the right by 2 units, so now our equation becomes y=-x+2

So basically you have a set of points that form a circle, with centre (4,4) and radius 2.
The distance from Origin to Centre = √(4²+4²) = 5.66
p = Ans - 2 = 3.66
q = Ans + 2 = 5.66

Wow!!!!!

Thanks a bunch............

 

[farhan141]

So basically you have a set of points that form a circle, with centre (4,4) and radius 2.
The distance from Origin to Centre = √(4²+4²) = 5.66
p = Ans - 2 = 3.66
q = Ans + 2 = 5.66

Can u do alpha and beta of this? I pasted this few days back but u disappeared and no one solved it... I'll quote all the problems in a few min, can u do them today or tmrw?