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Let me give it a try,i need help in a recent paper 2017 feb march paper 32
question number 5
any help would be appreciated
thank u in advance
y=e^(-ax)tanx
dy/dx=(-a)(e^-ax)(tanx)+(e^-ax)(secx^2)=0
a(e^-ax)(tanx)=(e^-ax)(secx^2)
atanx=1+tanx^2 -- secx^2=1+tanx^2
tanx^2-atanx+1=0
solve it simultaneously.