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Maths 2012 Paper 22

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What did you guys get for the shear matrix? The shear factor was 2. but the matrix i got was like

(1 3).
(0 2)

I got this by Multiplying the Original triangle Cordinates with (a b).
(c d)

So it was like- (2 3) * (a b)= (4 5)
(1 1) (c d) (1 1)

Am i correct? And also for the first quuestion the TRINGNOMETRY one, what was the answer for exatcly 2 lines of symmetry? and the one with Y varies directly as the ^2 of (x-3) what was the constant? i got 0.25.
 
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What did you guys get for the shear matrix? The shear factor was 2. but the matrix i got was like

(1 3).
(0 2)

I got this by Multiplying the Original triangle Cordinates with (a b).
(c d)

So it was like- (2 3) * (a b)= (4 5)
(1 1) (c d) (1 1)

Am i correct? And also for the first quuestion the TRINGNOMETRY one, what was the answer for exatcly 2 lines of symmetry? and the one with Y varies directly as the ^2 of (x-3) what was the constant? i got 0.25.
Assalam-o-alaikum wr wb...
well..the shear factor was 2
and the 2nd part was
8516.jpg
for second question...the first part was 'I' and the second one was 'I' and 'N'
i think yeah...it was 0.25..what was the final answer? may be i remember it after that :p
 
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But are you sure the K is 0.25? cause the answer only carries 1 marks, the rest is K and working. Some people got K as 4. The answer was same But the K was diff. My formula was (x-3)^2 = ky
well...that's for sure, the answer wasn't 4...i don't remember exactly but it was '0.' something! :p
 
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I think it was 0.25
it cant be because if u see both line were parallel so the value of c was given for both lines and c was half of the other c e.g c=10 in the line given with gradient and other was 5 and y=8 other was y=4 so its half the gradient given was 5 so it will be 2.5
 
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