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Maths, Addmaths and Statistics: Post your doubts here!

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No 8 x 7.5 ! U have to take upper bound !
they have asked for what? the smallest width that can ALWAYS hold 8 pencils, right? so we have to take the upper bound of the pencils's diameter. this is because if we take the lower bound of the pencils,6.5mm, the box could not hold 8 pencils if their actual diameter was more than 6.5 (which is totally possible) eg 7.5mm. what will happen then? the box could not hold 8 pencils. so in order for the box to hold the 8 pencils in ANY CASE, we will take upper bound of the diameter, ie 7.5mm
7.5mm*8 = 60 mm = 6 cm :)

thanks :)
 
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MustafaMotani pastpapers mein kahin per area k ratio me square liya hota hai kahin per nai to agr un mein koi b line common ho to square nai letey wrna lete hain? i don't understand this concept.
 
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for question 9 get the two equation you can easily deduce that one is y=3 and the shaded part is below it means lesser so it will be y<3 and for the other you can see that the equation which is already given has a intercept off -2 and you can deduce this line on the graph okay now you have to find the equation of third line take any two points from that line find gradient and equation from y-y1=m(x-x1) and the shaded area is on the right side so it means greater so we'll use > for that equation. hope you got!
 
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for question 9 get the two equation you can easily deduce that one is y=3 and the shaded part is below it means lesser so it will be y<3 and for the other you can see that the equation which is already given has a intercept off -2 and you can deduce this line on the graph okay now you have to find the equation of third line take any two points from that line find gradient and equation from y-y1=m(x-x1) and the shaded area is on the right side so it means greater so we'll use > for that equation. hope you got!
thanku :)
 
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