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Maths, Addmaths and Statistics: Post your doubts here!

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I know, told ya! Credit Stealer :p

But you can get this title too. Just work hard. Go and practice maths. :p
Once you get really good, tell me and i'll take a test of tough questions from you, and if you pass, you'll be given this title too.

Everyone deserves a chance. That's my rule.
 
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But you can get this title too. Just work hard. Go and practice maths. :p
Once you get really good, tell me and i'll take a test of tough questions from you, and if you pass, you'll be given this title too.

Everyone deserves a chance. That's my rule.
LOLX! thanks for the Motivations Bro :) May you get A*
 
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Hello
m new here :D
Can any one here tell me about varients? i mean is it just okay to solve pastpapers?
for taking examinations Cab university has divided the countries in 6 zones. and there is a different qp for every zone (all qp.s vary from each other) and thus these different exams papers are regarded as variants :)
 
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and
I'll just teach you how to do part a. ok? b part will be your test for taking the title of Maths Master from me :p dont worry its gonna be v easy.

ok, so coming to a)
first divide the number 280 into its prime factors.
and then multiply them to get

2x7x5 = 70 Done ,........... Tell me B

I can do it like

Factorization = 2 x 3 ^ 2 x 7 ^ 2

Multiply we 42, side of cube. so cube is = 42 * 42* 42= 74088
divide on 882 to get k = 84............


I wanna know is this right way to do?
 
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and

and then multiply them to get

2x7x5 = 70 Done ,........... Tell me B

I can do it like

Factorization = 2 x 3 ^ 2 x 7 ^ 2

Multiply we 42, side of cube. so cube is = 42 * 42* 42= 74088
divide on 882 to get k = 84............


I wanna know is this right way to do?
all i asked you was, to do this
2 * 2 * 2 * 5 * 7 = 280
 
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I just multiply Prime Factorization, not including the powers.....
Like in this case
2x5x7
nah wrong.

2 * 2 * 2 * 5 * 7 * k = 280k

when we find the squre root of 2 * 2, itl be ofcourse a single 2.
the same way under-root ( 2* 2 * 2 * 2) = 2 * 2
and underoot (2 * 2 * 2 * 2 * 2 * 2) = 2 * 2 * 2

so if we have 2 * 2 * 2, u need to multiply it with such a number that the total number of 2's becomes even
like, 2 * 2 * 2 * 2 is a proper square root.

the same way underoot(2 * 2 * 2 * 2 * 2 * 2 * 3 * 3 * 11 * 11) = 2 * 2 * 2 * 3 * 11
got it?

so all u need to do is, make the number of all prime factors 'even'
280k = 2 * 2 * 2 * 5 * 7 * k
280 k = 2 * 2 * 2 * 2 * 5 * 5 * 7 * 7

so k = 2 * 5 * 7

but if we had 1400 instead of 280 in the Question. where prime factors of 1400 are 2 * 2 * 2 * 5 * 5 * 7
we only need to to increase the number of all the prime factors which is divisible by 2 (coz we have to find SQUARE root, and if we had to find cube root, we'll increase the number of prime factors so that 'that' number of each of the prime factors is divisible by 3)
so we will do it this way 1400k = 2 * 2 * 2 * 2 * 5 * 5 * 7 * 7
k = 2*7

got it?
 
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for taking examinations Cab university has divided the countries in 6 zones. and there is a different qp for every zone (all qp.s vary from each other) and thus these different exams papers are regarded as variants :)
so its helpful to solv them
 
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and

and then multiply them to get

2x7x5 = 70 Done ,........... Tell me B

I can do it like

Factorization = 2 x 3 ^ 2 x 7 ^ 2

Multiply we 42, side of cube. so cube is = 42 * 42* 42= 74088
divide on 882 to get k = 84............


I wanna know is this right way to do?

Isnt that my method?:p:D
 
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