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Maths, Addmaths and Statistics: Post your doubts here!

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I think you should use y-y1 = m(x-x1) in every single case except where you need to find the Y intercept. The only other purpose of y = mx + c (to my knowledge) is to determine the gradient from looking at or rearranging the equation.
 
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BTW Thanks Guys for the help! :)

Well now Iam doing Loci and Construction;Iam a bit Confuse in a Question here its:
-> Construct a diagram,
(i): the triangle DEF,in which EF=10cm,DE^F=38* and DF^E=95*
(ii) the locus of points 4.5cm from F
(iii) the locus of points equidistant from DE and EF.
On your drawing,label the points P and W both of which are 4.5 from F and equidistant from DE and EF.Measure and write down the length PQ

Well,I have done till part 2 but iam confused in part 3 the Equidistant from DE and EF :no: :fool:
 
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Waleed007 said:
BTW Thanks Guys for the help! :)

Well now Iam doing Loci and Construction;Iam a bit Confuse in a Question here its:
-> Construct a diagram,
(i): the triangle DEF,in which EF=10cm,DE^F=38* and DF^E=95*
(ii) the locus of points 4.5cm from F
(iii) the locus of points equidistant from DE and EF.
On your drawing,label the points P and W both of which are 4.5 from F and equidistant from DE and EF.Measure and write down the length PQ

Well,I have done till part 2 but iam confused in part 3 the Equidistant from DE and EF :no: :fool:
In this part u have to draw an angle bisector.
Because there is a common side E given.
 
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SalmanPakRocks said:
Waleed007 said:
BTW Thanks Guys for the help! :)

Well now Iam doing Loci and Construction;Iam a bit Confuse in a Question here its:
-> Construct a diagram,
(i): the triangle DEF,in which EF=10cm,DE^F=38* and DF^E=95*
(ii) the locus of points 4.5cm from F
(iii) the locus of points equidistant from DE and EF.
On your drawing,label the points P and W both of which are 4.5 from F and equidistant from DE and EF.Measure and write down the length PQ

Well,I have done till part 2 but iam confused in part 3 the Equidistant from DE and EF :no: :fool:
In this part u have to draw an angle bisector.
Because there is a common side E given.
When the word 'EQUIDISTANT' Comes we should always draw angle bisector?
 
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Well I think an Angle Bisector should be drawn yet i m not conformed about it! I forgot most of the topics in maths.
Yet I think we will draw an Angle bisector.
 
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SalmanPakRocks said:
Well I think an Angle Bisector should be drawn yet i m not conformed about it! I forgot most of the topics in maths.
Yet I think we will draw an Angle bisector.
So we can draw angle by sector in any question when the word EQUIDISTANT from EF and FG right?
 
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When the question highlights the following do as stated !

1.equidistant from two lines like AB and AC go for an angle bisector !
2.When it says equidistant from two points A and B u make a perp bisector !
3.When it says equidistant to one point like C a circle needs to be drawn !
4.ANd when it is equidistant from one line like PQ u draw parallel lines above and below this line !

thats it ur LOCI is done but yeah sometimes u have these difficult questions that can derail ur concepts ! :D 8)
 
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We can Use any length right?......Like to construct a triangle,Rhombus,Quadrilateral etc
 
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