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Maths, Addmaths and Statistics: Post your doubts here!

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I'm going to start paper 1's tonight. Which year should i start from?
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Kevin takes T time with 100 speed.
Jane takes ___ time with 110 speed.

T is inversely proportional to speed.

So T = k/speed.

Put 100 and T in, and you get k=100T

Then, put 110 as speed, and you get the time for Jane, 100T/110
Kevin's time = T

Kevin's speed = d/T

Jane walks 10 % faster than Kevin (her speed is 10 % more than Kevin)

Jane's speed = (d/T) * (110/100)


Applying the speed = distance/ time formula


(d/T) * (110/100) = d / x

Find x
thx:cool:
 
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