Maths, Addmaths and Statistics: Post your doubts here!

[syed1995]

12 1/2 divded by 3 3/2
post reply quickly plz

(12*2+1) / 2 / (2*3+3)/2

25/2 / 9/2

25/2 * 2/9

25/9

2 7/9

 

[Durrani]

acha btao na .. ye kia hota hai .. !! also what is shear factor?

like agar (2,0) (0,2) (4,0) (0,4) houn co-ordinates aur shear factor 3 ho .. tu final co ordinates kia hongay ..

case 1 x axis invariant
case 2 y axis invariant.

in case 1, (6,0) (0,2) (12,0) (0,4) points on invariant line dnt move

 

[syed1995]

12 1/2 divded by 3 3/2
post reply quickly plz

√12 / √3^3
(√2*2*3) /(√3*3*3)
(2√3) / (3√3)
2/3 Answer.

 

[Durrani]

√12 / √3^3
(√2*2*3) /(√3*3*3)
(2√3) / (3√3)
2/3 Answer.

thank u

 

[Mayedah]

http://www.xtremepapers.com/papers/...(Calculator Version) (4024)/4024_s04_qp_1.pdf
Question no 21 part b !

 

[syed1995]

thank u

just remember whenever there is square roots involved .. or factors involved ..

divide that number into its primary factors .. if you're not in much practice .. just take the LCM!

 

[convent2012]

How to convert a Speed Time graph into A Distance Time graph??

 

[convent2012]

i need notes on
locus
upper bond , lower bond
inequalities graphes !!!

 

[syed1995]

http://www.xtremepapers.com/papers/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_s04_qp_1.pdf
Question no 21 part b !

k=0.5 .. y=0.5 when x=0 .. anything to the power of 0 = 1 so 0.5=1*k.

on x=1 y=1.8

on x=1 equation will be y=ka
1.8=0.5a
a=3.6


I wish i had remembered that in addmaths !!

 

[syed1995]

How to convert a Speed Time graph into A Distance Time graph??

note the time for all the constant ones and all lines .. get the area under the curve .. and then plot the graph!

 

[convent2012]

note the time for all the constant ones and all lines .. get the area under the curve .. and then plot the graph!

u mean total time and total distance ??

 

[syed1995]

u mean total time and total distance ??

Yeah!

 

[Durrani]

http://www.xtremepapers.com/papers/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_s04_qp_1.pdf
Question no 21 part b !

look for value of x to be zero. then a will become one and u will get K = 0.5.. then using k and any one value of x,y, find a..

 

[convent2012]

Yeah!

okay

 

[syed1995]

i need notes on
locus
upper bond , lower bond
inequalities graphes !!!

Locus

http://www.mathopenref.com/constbisectline.html
http://www.mathopenref.com/constbisectangle.html

 

[convent2012]

Locus

http://www.mathopenref.com/constbisectline.html
http://www.mathopenref.com/constbisectangle.html

thanku

 

[convent2012]

Locus

http://www.mathopenref.com/constbisectline.html
http://www.mathopenref.com/constbisectangle.html

could you plz explain the upper bond and lower bond ??

 

[syed1995]

could you plz explain the upper bond and lower bond ??

Upper And Lower bound depends on the Accuracy ..

if its to the nearest cm.

and the question is written 5.53m

we will first change it to cm.

553cm .. then nearest to CM

means to the first unit after decimal or one per say .. we will then find possible error .. it is always the unit/2

unit here is 1

so PE=1/2

now for upper bound we add the PE and for lower bound we subtract the PE.

UB= 553.5
LB= 552.5

To the nearest 100 will be like ..

PE = 100/2
PE = 50

so we will add and subtract 50 from the final answer.

 

[syed1995]

And now I am headed to bed.. cya later people.

 

[convent2012]

Upper And Lower bound depends on the Accuracy ..

if its to the nearest cm.

and the question is written 5.53m

we will first change it to cm.

553cm .. then nearest to CM

means to the first unit after decimal or one per say .. we will then find possible error .. it is always the unit/2

unit here is 1

so PE=1/2

now for upper bound we add the PE and for lower bound we subtract the PE.

UB= 553.5
LB= 552.5

To the nearest 100 will be like ..

PE = 100/2
PE = 50

so we will add and subtract 50 from the final answer.

thanks again
its now pretty clear