Maths, Addmaths and Statistics: Post your doubts here!

[syed1995]

wAH

If a workforce of 20 can produce 12 cars in 15 days, how many workers should be used if 15 cars are needed in 10 days?

 

[Fallen316]

wAH

i mean till '07

 

[beeloooo]

http://clickpapers.net/past papers/math-/4024_w02_er.pdf Q.19 PART (A) !!

 

[haha101]

you both have got the logic correct but are doing it wrong!
for the first three co linear points B C and D, they have given the variable "k" . you cant assign the same variable to a different set of colinear points, ie F E and D. so you have to intriduce a new variable, eg "c"

FD = c FE
(3-4k)p + 2kq = -cp + cq
from comparing variables of q:
c= 2k
now compare variables of p:
3-4k = -(2k)
3=4k-2k
k=3/2!

Comparing mei p ki terms ko equate karey gey n then q ki ! like simultaneous equations ! right ?

 

[MustafaMotani]

i mean till '07

wo to aur achi baat hai... mein ne ek b nhe kia..

 

[beeloooo]

@fallen 316 can u solve this pls ??

 

[syed1995]

wo to aur achi baat hai... mein ne ek b nhe kia..

tumhein zaroorat hi kahan hai ...

 

[Fallen316]

@fallen 316 can u solve this pls ??

which one ?

 

[MustafaMotani]

If a workforce of 20 can produce 12 cars in 15 days, how many workers should be used if 15 cars are needed in 10 days?

37.5 ans hai .??

 

[MustafaMotani]

tumhein zaroorat hi kahan hai ...

nhe yar aesa nhe hai

 

[beeloooo]

which one ?

http://clickpapers.net/past papers/math-/4024_w02_qp_1.pdf !!! q.19 part (a)

 

[Vogue]

dekho
t is inversely proportionl to area
so T= k /A
40=k/3
k=120 (constant)

now Area is 4 so time should be
T=120/4 = 30mins
lekin usne sirf 9 mins chalaya to to kitna container full hoga. ??
9/30 = 3/10

thank u mustafa.

 

[Fallen316]

http://clickpapers.net/past papers/math-/4024_w02_er.pdf Q.19 PART (A) !!

F is inversely proportional to d^2
F = k/d^2 -----> eq.1
F = 10N and let the distance be x
10 = k/x^2
k = 10x^2
now, we have to find the force when the distance is doubled . i.e 2x
substitute the new distance and value of k in eq.1
F = 10x^2/(2x)^2
F = 5/2
F = 2.5 ---> ANS

 

[haha101]

37.5 ans hai .??

kesey aya man ????

 

[MustafaMotani]

thank u mustafa.

u got it ??

 

[syed1995]

37.5 ans hai .??

han ab tareeka btao

 

[beeloooo]

F is inversely proportional to d^2
F = k/d^2 -----> eq.1
F = 10N and let the distance be x
10 = k/x^2
k = 10x^2
now, we have to find the force when the distance is doubled . i.e 2x
substitute the new distance and value of k in eq.1
F = 10x^2/(2x)^2
F = 5/2
F = 2.5 ---> ANS

thank u so much

 

[syed1995]

Actually I got it..

25*15/10 to get the final answer

 

[Vogue]

u got it ??

yes i did

 

[haha101]

yaar tum logon ki tyari tou itna aala hai ! Yahan sey tou sari distinction aey gi Ab thori help yahan bhi kardo ! Please tell me sawal I can practice to improve ! Give me the most hardest you have come across please !