Maths, Addmaths and Statistics: Post your doubts here!

[UziB]

Can someone tell me how do we find the invariant line in cases of stretch/shear?

 

[Ahmedfj]

Can someone tell me how do we find the invariant line in cases of stretch/shear?

the line on which the base of the figure remains the same

 

[Ahmedfj]

Can someone tell me how do we find the invariant line in cases of stretch/shear?

Q17 ppr 12 novemeber 2011 both parts .. help needed pls

 

[UziB]

the line on which the base of the figure remains the same

I know it's definition aswell but I mean how do we find it in cases for e.g Q27 part b of this paper http://www.xtremepapers.com/papers/...Calculator Version) (4024)/4024_w11_qp_12.pdf

 

[Ahmedfj]

I know it's definition aswell but I mean how do we find it in cases for e.g Q27 part b of this paper http://www.xtremepapers.com/papers/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_w11_qp_12.pdf

Y = 3 i guess coz its the only line which is common in both figures i.e it does not change

 

[UziB]

Q17 ppr 12 novemeber 2011 both parts .. help needed pls

To find the boundary error, you always divide the given unit in the question by 2. Which in this case is the nearest millimeter, hence the boundary error will be 1mm/2 = 0.5mm. Lower bound means subtracting the boundary error from the given value in the question and upper bound means adding the boundary error to the given value in the question which in this case is 57 so upper bound = 57 + 0.5 = 57.5mm.
Perimeter of square = 4L. You have the upper bound for one side of the square, convert it into cm i.e 5.75cm. Then find the perimeter via 4L = 4 X 5.75 cm.

 

[UziB]

Y = 3 i guess coz its the only line which is common in both figures i.e it does not change

It's x = -1 in the mark scheme.

 

[Mayedah]

It's x = -1 in the mark scheme.

Only x =-1 gives u the scale factor 2 !

 

[khizer shahab]

http://www.xtremepapers.com/papers/...(Calculator Version) (4024)/4024_w09_qp_1.pdf

question 7 with method

q19 part B

and q24 part B , actually how to find the gradient of the line !!!

if the line is parrallel to x axis then gradient would be zero and if placed in equation the product for x coordinate is coming 0

y=mx+c ---> (2)=0*x +c

.....................coordinate = (0.2)

q21 part B too

and at last 25 part i also

for it i applied the formula image=object + translation matrix

[ +4 ].... [ 1] [x]
[ -7 ] = [2] + [y]

but getting wrong !!


pleeez help me soon !!!!! syed1995

 

[khizer shahab]

pls anyoen help me in bound question

in bound questions you just simply have to minus for the lower and add for upper 0.5 of the same unit !!!

 

[syed1995]

http://www.xtremepapers.com/papers/...(Calculator Version) (4024)/4024_w09_qp_1.pdf

question 7 with method

q19 part B

and q24 part B , actually how to find the gradient of the line !!!

if the line is parrallel to x axis then gradient would be zero and if placed in equation the product for x coordinate is coming 0

y=mx+c ---> (2)=0*x +c

.....................coordinate = (0.2)

q21 part B too

and at last 25 part i also

for it i applied the formula image=object + translation matrix

[ +4 ].... [ 1] [x]
[ -7 ] = [2] + [y]

but getting wrong !!


pleeez help me soon !!!!! syed1995

Janab aap hain isi waja say solve kar rahay hain warna iss waqt khud ka revision chal raha hai ..

Q7. dekho bhai into 20 means .. 2 x 10^1

6.9*2 = 13.8 x 10^7 *10
13.8 x 10^8
1.38 x 10^9
Yaanay kay China .. cuz that's closest

Q19 b

substitute value of y ..

2(3)^2 + 3k -27=0
18+3k-27=0
3k=9
k=3

2y^2 + 3y - 27 = 0 ab tu solve karlo gay naaa ??? iss kay 2 answer aayeingay .. aik 3 aur aik - 9/2.

Q21 b

5/8 * 4/7
20/56 lowest term khud nikal lena ...

(5/8 * 3/7) + (3/8*5/7)


Q 24 b Aankhein tu kholo .. 2 already given hain ... 2y = 3x + 5 and x + 4y = 24

and third khud nikal loo .. y>-3 MN wali line jo hai ..

inequality sign question ko dekh kay lagta hai .. i guess wo tu aata hoga ..

Q25 Bhai konsa part???

 

[khizer shahab]

Janab aap hain isi waja say solve kar rahay hain warna iss waqt khud ka revision chal raha hai ..

Q7. dekho bhai into 20 means .. 2 x 10^1

6.9*2 = 13.8 x 10^7 *10
13.8 x 10^8
1.38 x 10^9
Yaanay kay China .. cuz that's closest

Q19 b

substitute value of y ..

2(3)^2 + 3k -27=0
18+3k-27=0
3k=9
k=3

2y^2 + 3y - 27 = 0 ab tu solve karlo gay naaa ??? iss kay 2 answer aayeingay .. aik 3 aur aik - 9/2.

Q21 b

5/8 * 4/7
20/56 lowest term khud nikal lena ...

(5/8 * 3/7) + (3/8*5/7)


Q 24 b Aankhein tu kholo .. 2 already given hain ... 2y = 3x + 5 and x + 4y = 24

and third khud nikal loo .. y>-3 MN wali line jo hai ..

inequality sign question ko dekh kay lagta hai .. i guess wo tu aata hoga ..

Q25 Bhai konsa part???

thank you very very much yar !! thousand of like for you ....for question 25 part (a)(i)

and pls also the question 21 part (b)(ii)

 

[syed1995]

T= I - O
T = -7,4 - 1,2
T= -8/2

21 b ii
(5/8 * 3/7) + (3/8*5/7) + (5/8*4/7)
boy/girl + girl/boy + boy/boy

 

[khizer shahab]

Janab aap hain isi waja say solve kar rahay hain warna iss waqt khud ka revision chal raha hai ..

Q21 b

5/8 * 4/7
20/56 lowest term khud nikal lena ...

(5/8 * 3/7) + (3/8*5/7)

yar 21 b ii ka answer ms mein 25/28 hai

 

[syed1995]

yar 21 b ii ka answer ms mein 25/28 hai

barri jaldi quote kardia aap nay .. mein question set hi kar raha tha dobara dekhiye..

 

[syed1995]

Ya sab chorro .. seedha seedha ... girl/girl nikalo ..

3/8 * 2/7

aur 1 say minus kardo .. isi tarah mein karta iss question ko ...

 

[khizer shahab]

barri jaldi quote kardia aap nay .. mein question set hi kar raha tha dobara dekhiye..

really tense yar i am loosing almost 6-7 just for my silliness !!!

 

[khizer shahab]

Ya sab chorro .. seedha seedha ... girl/girl nikalo ..

3/8 * 2/7

aur 1 say minus kardo .. isi tarah mein karta iss question ko ...

oh ,, i ave been taught this method

thank you very much again !!

 

[khizer shahab]

ok syed1995 and all other appering for maths very best of good lucks and may ALLAH truly help us to gain A*
bye syed1995 !!

 

[syed1995]

ok syed1995 and all other appering for maths very best of good lucks and may ALLAH truly help us to gain A*
bye syed1995 !!

Bye. Insha Allah A* hi aayega maths mein .. aur aaj kay paper mein 80/80.