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Maths, Addmaths and Statistics: Post your doubts here!

syed1995

syed1995

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beeloooo said:
http://clickpapers.net/past papers/math-/4024_w10_qp_22.pdf


q.5 last part !! i don't know how to calculate the width and height of the bar pls if anyone can explain it plz ? :O
Click to expand...

height=frequency density.

Frequency density= frequency/class interval

so for 90-95 .. the class interval = 95-90 = 5

FD = F/X
FD = 20/5
FD = 4

so the height of 90-95 = 4 and the width = class width = 5.

I guess you can take it for the rest yourself now.
 
Vogue

Vogue

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syed1995 said:
Yes. that's what i was arguing about last night with a couple of guys, when they say no rotational symmetry it basically means it only has the one rotational symmetry which every shape has.
Click to expand...
yes xactly every shape must hv 1 rotational order of symmetry. so 1 R.O.S is called zero R.O.S???
nd a shape which will hv 2 R.O.S that is one of its own nd 1 wen it will turn full 360 degrees, will said to hv 1 R.O.S???
 
B

beeloooo

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syed1995 said:
height=frequency density.

Frequency density= frequency/class interval

so for 90-95 .. the class interval = 95-90 = 5

FD = F/X
FD = 20/5
FD = 4

so the height of 90-95 = 4 and the width = class width = 5.

I guess you can take it for the rest yourself now.
Click to expand...

the answer is 1 and 10 :O
 
Vogue

Vogue

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beeloooo said:
the answer is 1 and 10 :O
Click to expand...
ok c! lets calculate frequency density which is also called height. for less than or equal to 90, it is 16/10=1.6
for less than or equal to 95, it is 20/5=4
now class width of 10 represents width of 2 cm
class width of 5 will represent 1 cm
freq density of 1.6 represents height of 4 cm
freq density of 4 will represent height (4/1.6)4=10
 
syed1995

syed1995

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beeloooo said:
the answer is 1 and 10 :O
Click to expand...


"The rectangle representing the apples with masses in the interval 80  m  90 has width
2 cm and height 4 cm."


use that to equate it to scale. I was just telling you 'how' to take out the class width and frequency density.
 
S

SALT

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HarisLatif said:
for Q9ciii ; as you have worked out that AN is 6 so BM is also 6 since BMQ and ANP are congruent. and if BM is 6 then BN will be 12 since B Is the centre of enlargment and scale factor is 2. so BN-BM=12-6=6. Hope you get it.
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thnx 4 ur help, but why would BMQ and ANP be congruent? the question says APB and BQC....
and plz solve Q8 too...:)
 
daredevil

daredevil

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HEyy guys!! the nightmare question for me:
w11_4042 paper 22 question 8(c)(iii) ......... plz hury up and tell me how we can calculte calues for B and C!!
 
HarisLatif

HarisLatif

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scouserlfc said:
Its a combined transformation of some kind but it never asks to define so why wwaste time thinking abt it :D
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yeah but we first have to know this before finding the cordinates of its image as asked in the question. i don't know how to get them
 
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