Maths, Addmaths and Statistics: Post your doubts here!

[pakiboy]

i got it directly

k me 2!!!!!! gud luck for tmrw..... dude

 

[Jaguar]

i

http://www.xtremepapers.com/papers/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_w11_qp_22.pdf

How to do 9 c)iii)b)..?

i'm not sure but i would say AN = MB = 6. M is the midpoint of NB. Hence, NM = NM = 6 cm

 

[lisahamed]

http://www.xtremepapers.com/papers/...Calculator Version) (4024)/4024_w11_qp_22.pdf
could anyone help me out with no.9 (c) (iii) (b) and (c) .... any help would be appreciated

 

[asd]

http://www.xtremepapers.com/papers/...Calculator Version) (4024)/4024_s11_qp_22.pdf
Q 11 b 1v, how to find the total surface area? I guess the ms is wrong!

 

[kitecrystal]

k me 2!!!!!! gud luck for tmrw..... dude

same to u

 

[SilverCrest]

i
i'm not sure but i would say AN = MB = 6. M is the midpoint of NB. Hence, NM = NM = 6 cm

i got it..!
through triangel ANB being congruent to BMC
hence BM=AN

thanks!

 

[asd]

http://www.xtremepapers.com/papers/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_s11_qp_22.pdf
Q 11 b 1v, how to find the total surface area? I guess the ms is wrong!

Ahh, my bad. I got it.

 

[SilverCrest]

http://www.xtremepapers.com/papers/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_w11_qp_22.pdf
could anyone help me out with no.9 (c) (iii) (b) and (c) .... any help would be appreciated

in b)
<APM =<MBC(alternate angles)
<ABP=<BCQ

as they are in a rite angeld traiangle they add up to 90
the same is the case in triangle BMC

 

[SilverCrest]

in b)
<APM =<MBC(alternate angles)
<ABP=<BCQ

as they are in a rite angeld traiangle they add up to 90
the same is the case in triangle BMC

uh my bad did u mean c)iii)b) and c)
in b)
ANB and BMC are congruent
so AN=BM
BM=MN (because they are halves of BN

in c)
MC=BN=6+6=12

 

[MustafaMotani]

So is everyones preparation good.. ??

 

[moni]

can any 1 give some angle properties of circle..quick revision?

 

[Muhammad Zain Qasmi]

VERY LAST PART PLEASE ? :S (e)(iii)

 

[Muhammad Zain Qasmi]

GOT IT GOT IT GOT IT ! Thanks anyway

 

[MustafaMotani]

GOT IT GOT IT GOT IT ! Thanks anyway

gr8 ..

 

[asd]

http://www.xtremepapers.com/papers/...Calculator Version) (4024)/4024_w11_qp_22.pdf
Q 3 a (ii)
Shouldnt that ratio be 1:10 and not 10:1
Because obviously the larger Radius will be greater than smaller radius.

 

[MustafaMotani]

can any 1 give some angle properties of circle..quick revision?

angle at centre twice the angle at circumference
angle subtended by same arc/angle in same segment with same cord are equal
when all four points of quadrilateral lie on circumfernece of circle then sum of opposite angles is equal to 180
angle in semi circle wid diameter as base will always be 90

aur yaad nhe arahi

 

[MustafaMotani]

http://www.xtremepapers.com/papers/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_w11_qp_22.pdf
Q 3 a (ii)
Shouldnt that ratio be 1:10 and not 10:1
Because obviously the larger Radius will be greater than smaller radius.

ha so its R^2:r^2

 

[asd]

ha so its R^2:r^2

So its 1:10 naa?

 

[asd]

So its 1:10 naa?

Oh, my bad.

 

[MustafaMotani]

So its 1:10 naa?

no 10 : 1
u yourself said taht larger radius should be larger so its 10 : 1
question is asnking R : r not r : R