Maths, Addmaths and Statistics: Post your doubts here!

[Saad Mughal]

Saad Mughal


Now this one.. only the first part... a(i) and (iii)

(i) 120 [x + (x-1) + (x+1)] = x(x-1)(x+1)
120 (3x) = x (x^2 - 1)
360x = x^3 - x
x^3 - 361x = 0

(iii) x(x^2-361) = 0
either x = 0,
or, x = +- underroot 361,
x= 0, 19, -19.

 

[Saad Mughal]

Pride isn't something good, you know . Just believe in yourself and leave the rest to Allah.


LOL

By pride, I meant that believe that I can get one only in Maths.

 

[fatima0000]

http://papers.xtremepapers.com/CIE/...Calculator Version) (4024)/4024_w12_qp_21.pdf
Q 10 (c)

 

[farhan141]

By pride, I meant that believe that I can get one only in Maths.

Oh ok, sozz my bad

 

[farhan141]

http://papers.xtremepapers.com/CIE/...Calculator Version) (4024)/4024_w12_qp_21.pdf
Q 10 (c)

You're still on this paper?

 

[starship]

(i) 120 [x + (x-1) + (x+1)] = x(x-1)(x+1)
120 (3x) = x (x^2 - 1)
360x = x^3 - x
x^3 - 361x = 0

(iii) x(x^2-361) = 0
either x = 0,
or, x = +- underroot 361,
x= 0, 19, -19.

a2

 

[starship]

(i) 120 [x + (x-1) + (x+1)] = x(x-1)(x+1)
120 (3x) = x (x^2 - 1)
360x = x^3 - x
x^3 - 361x = 0

(iii) x(x^2-361) = 0
either x = 0,
or, x = +- underroot 361,
x= 0, 19, -19.

a 2

x(x-19)(x+19)

right?

 

[farhan141]

Transformation Matrices are super easy. Anyone facing problems, lemmee know

 

[farhan141]

Actually ask Saad. I'm gonna sleep. Bye and Good Luck to all except asma and saad. Jk

 

[Saad Mughal]

http://papers.xtremepapers.com/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_w12_qp_21.pdf
Q 10 (c)

320/x-80 - 320/x = 2.5
320x - 320 x + 25600/ x^2 - 80x = 2.5
2.5x^2 - 200x - 25600 = 0
2.5 (x^2 - 80x - 10240) = 0
x^2 - 80x - 10240 = 0

 

[starship]

Transformation Matrices are super easy. Anyone facing problems, lemmee know

meee

 

[asma tareen]

Transformation Matrices are super easy. Anyone facing problems, lemmee know

meeee

 

[Saad Mughal]

I just rattafied them.

 

[starship]

Actually ask Saad. I'm gonna sleep. Bye and Good Luck to all except asma and saad. Jk

seriously..

 

[asma tareen]

I just rattafied them.

tell me thn

 

[SamiaSaad]

Best of luck everyone.....

 

[Saad Mughal]

tell me thn

RATTA marlayn.

 

[asma tareen]

Best of luck everyone.....

same to u

 

[farhan141]

meee

Look, all you need to do is make a graph sketch.

Mark a scale of 1 on all 4 axis. Then change the points according to the transformation.

I'll take one example,

Let's say it's a reflection with y-axis as invariant line. This means that there will be no change in the y co-ordinates.

The original matrix would have been

(1 0)
0. 1

but now it changes to

(0 -1)
1. 0

 

[asma tareen]

RATTA marlayn.

abey btao to sai jo ratta maarun