Maths, Addmaths and Statistics: Post your doubts here!

[kirann]

KIRAN post a question and tell us what problems you face

ok i have dozens of them ill post it

 

[sameersuleman]

k.

ok i have dozens of them ill post it

 

[Bhaijan]

Can someone explain what's going on here? This question went through my head!
Its from 4024_w02_qp_1

 

[Asad.Babur]

Can someone explain what's going on here? This question went through my head!
Its from 4024_w02_qp_1
View attachment 41397

Its simple let Student study GEO and History be X
and student who study geo (8) = G

So we know its G + X + 2G = 30

So when g = 8

8 + X + 16 = 30

X=6

 

[Bhaijan]

Its simple let Student study GEO and History be X
and student who study geo (8) = G

So we know its G + X + 2G = 30

So when g = 8

8 + X + 16 = 30

X=6

Good Job Bro, the answer is 3, after 6 is divided by 2

 

[Asad.Babur]

Good Job Bro, the answer is 3, after 6 is divided by 2

Ohh Forgot the last step, ...... NP

 

[quadfire]

Hi, Is the Casio 991-ES calculator allowed in maths and add maths?

 

[Asad.Babur]

Hi, Is the Casio 991-ES calculator allowed in maths and add maths?

Yes, in Maths it is. However, I am not sure of addmaths

 

[kirann]

can somebody explain?

 

[kirann]

this one too facing problem in part b and c(ii)

 

[Asad.Babur]

View attachment 41541
View attachment 41542
this one too facing problem in part b and c(ii)

Wait for 2 hours and I will do..............

 

[Asad.Babur]

View attachment 41538
can somebody explain?

I will sonn tell you how to do it . Just wait

 

[kirann]

I will sonn tell you how to do it . Just wait

ok

 

[FLRNAB]

View attachment 41538
can somebody explain?

Universal Set = {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18}
A = {2,4,6,8,10,12,14,16,18}
B = {5,10,15}

i) U for Union, N for Number of Elements
So 'A U B' = {2,4,5,6,8,10,12,14,15,16,18}
n(A U B) = 11

ii) Inverted ∩ for Intersection
A ∩ B' ∩ C' => (A ∩ B') ∩ C'

Solve Part by Part:
1)
A = {2,4,6,8,10,12,14,16,18}
B' = {2,3,4,6,7,8,9,11,12,13,14,16,17,18}
A ∩ B' = {2,4,6,8,12,14,16,18}

2)
{2,4,6,8,12,14,16,18} ∩ C' = {2,6,14,18}
This {2,4,6,8,12,14,16,18} is same as Set A
C' is the set containing elements which are not in set C.

C' ∩ A = Common Elements of C' and A.
So C will not contain {2,6,14,18} as they are in C'.
C is a subset of A.
C will only contain A - C' which is {4,8,12,16}

iii) Multiples of 4

See this

 

[Asad.Babur]

Firstly, Sorry........ Ajj mera bhi Paper tha Pak Studies ka soooooooo, It took me looooooong to get back to you!

View attachment 41541
View attachment 41542
this one too facing problem in part b and c(ii)

See this

If you face Further Problem! Tell me>
hope it helps

 

[Asad.Babur]

View attachment 41541
View attachment 41542
this one too facing problem in part b and c(ii)

Let the Radius of Bigger Circle be R

So

(R^2*pi)-(15^2*pi)=1206

Solution:

Solve second Bracket, (R*R*pi)-(706.95)=1206
Replace Pie (R*R*3.142)-706.95=1206
Add 706.95 to Both sides
R*R*3.142=1912.95

Now Divide both sides by 3.142,
R*R=608.83
R=Square root 608.83
R=24.68

Check by Replacing in Equation or Marking Scheme

Thanks

 

[kirann]

Let the Radius of Bigger Circle be R

So

(R^2*pi)-(15^2*pi)=1206

Solution:

Solve second Bracket, (R*R*pi)-(706.95)=1206
Replace Pie (R*R*3.142)-706.95=1206
Add 706.95 to Both sides
R*R*3.142=1912.95

Now Divide both sides by 3.142,
R*R=608.83
R=Square root 608.83
R=24.68

Check by Replacing in Equation or Marking Scheme

Thanks

ok thanks

 

[kirann]

Universal Set = {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18}
A = {2,4,6,8,10,12,14,16,18}
B = {5,10,15}

i) U for Union, N for Number of Elements
So 'A U B' = {2,4,5,6,8,10,12,14,15,16,18}
n(A U B) = 11

ii) Inverted ∩ for Intersection
A ∩ B' ∩ C' => (A ∩ B') ∩ C'

Solve Part by Part:
1)
A = {2,4,6,8,10,12,14,16,18}
B' = {2,3,4,6,7,8,9,11,12,13,14,16,17,18}
A ∩ B' = {2,4,6,8,12,14,16,18}

2)
{2,4,6,8,12,14,16,18} ∩ C' = {2,6,14,18}
This {2,4,6,8,12,14,16,18} is same as Set A
C' is the set containing elements which are not in set C.

C' ∩ A = Common Elements of C' and A.
So C will not contain {2,6,14,18} as they are in C'.
C is a subset of A.
C will only contain A - C' which is {4,8,12,16}

iii) Multiples of 4

See this

i got it thanks for the link
do you have any link like this for transformation as well?

 

[Asad.Babur]

i got it thanks for the link
do you have any link like this for transformation as well?

Try
KhanAcademy.org, wide resource for Maths

 

[kirann]

Try
KhanAcademy.org, wide resource for Maths

no videos for transformation bro
it has some weird and diff type of transformation