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No, like others said, you can just figure it out through trial and error. The formula is just a more consistent method.That's a big formula :/ For changing difference. Is this a part of our syllabus?
Whats the year and question?
Sorry. .-. This is for the single common differnce. For this there's another formula.There's a formula, use that.
a+(n-1)d1
a is the first term of sequence and d is the common difference.
No, like others said, you can just figure it out through trial and error. The formula is just a more consistent method.
Oct-nov 2005, question 6(b)
It is (n+2)(n+1)/2Oct-nov 2005, question 6(b)
aesehiWhy are you doing paper 2? .-.
going back from 2013 ........what years r u guys focusing? exploded diper funky brat and otherssssssssss
A is shear i guys with x being invarienthttp://papers.xtremepapers.com/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_s04_qp_1.pdf
question 26, can anyone help with it?
nope paper onePaper 2 :/ Don't we have paper 1 on monday?
Ok i finally got it.In such complex patterns there is always a hint given in the above sequence and we have to make a relation with the one above and the one we have to find,this is a rule.So here we can see that each number below is increased by n and +1 e.g 2nd was 3 in first pattern but in next it was 3+2(number of sequence) + 1 and so on.Hence we can insert this in the formula given above to derive it.Final formula would beThe trial and error isn't working here. ^^
observe how is every next term changing.How? .-.
whats 1 for in the formulaSorry. .-. This is for the single common differnce. For this there's another formula.
What?whats 1 for in the formula
i didnt get the formula....What?
http://papers.xtremepapers.com/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_s04_qp_1.pdf
question 26, can anyone help with it?
u should focus on paper 1......seriously.....tu kia huwa![]()
what if the difference of the difference keeps changing ?What?
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