Maths, Addmaths and Statistics: Post your doubts here!

[exploded diper]

draw kar day paint pay bhai ya bracket lga

paint nahi hai.....magar jesay flnrab likh raha tha waisay tha...... shouray se...

 

[exploded diper]

Yes as it would be locus of points outside quadilateral/figure/etc


Arcs are to aid you in drawing the locus and they are not part of the locus so they need not be erased but anything part of the locus and not within the boundary should be erased.

can u simplify it more into indices form...

 

[Mahnoorfatima]

http://papers.xtremepapers.com/CIE/...(Calculator Version) (4024)/4024_w03_qp_1.pdf
Question 22part e? For cos how are we supposed to find the adjacent? We got the hypotenuse but what about adjacent? Anyone?

 

[funky brat]

Can somebody explain what shear and stretch is? :/
http://papers.xtremepapers.com/CIE/...Calculator Version) (4024)/4024_w12_qp_22.pdf
Question 11b part i) How do I reflect this? .-.

 

[exploded diper]

Can somebody explain what shear and stretch is? :/
http://papers.xtremepapers.com/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_w12_qp_22.pdf
Question 11b part i) How do I reflect this? .-.

 

[funky brat]

thanks.

 

[exploded diper]

http://papers.xtremepapers.com/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_w03_qp_1.pdf
Question 22part e? For cos how are we supposed to find the adjacent? We got the hypotenuse but what about adjacent? Anyone?

cos abc = - cos (180 - abc)
adjacent = 1 - (- 5) = 6

 

[asadalam]

http://papers.xtremepapers.com/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_w03_qp_1.pdf
Question 22part e? For cos how are we supposed to find the adjacent? We got the hypotenuse but what about adjacent? Anyone?

Extend A downwards and BC horizontally to the right until the meet to form a right angled triangle with AB as hypotenuse.The point where the extended lines is D. AD=8 units and BD=6 units,and AB is 10 which we have found previously.

Cos ABD = 6/10
Cos ABC= -(6/10)= -3/5

 

[Uchiha-Sasuke]

Thought would be helpful

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[A.Sagheer]

http://papers.xtremepapers.com/CIE/...Calculator Version) (4024)/4024_w10_qp_12.pdf
Q25 anyone?
And whats the general method of solving such questions which have a couple of variables?

 

[exploded diper]

http://papers.xtremepapers.com/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_w10_qp_12.pdf
Q25 anyone?
And whats the general method of solving such questions which have a couple of variables?

wait a sec....

 

[exploded diper]

http://papers.xtremepapers.com/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_w10_qp_12.pdf
Q25 anyone?
And whats the general method of solving such questions which have a couple of variables?

There u go....hope u get it...

 

[Uchiha-Sasuke]

http://papers.xtremepapers.com/CIE/Cambridge International O Level/Mathematics D (Calculator Version) (4024)/4024_w10_qp_12.pdf
Q25 anyone?
And whats the general method of solving such questions which have a couple of variables?

D= 1/2*20*u= 10u
2D= 20u
find an area thats 20u
form interval 20-40 there's a rectangle
20*u= 20u area
but D was already used from triangle (half was already used)
so take the interval of 20-30 for a rectangle
Now area of rectangle = 10*u= 10u
triangle area + rectangle = 10u +10u= 20u (which is 2D)
so 30 s

 

[A.Sagheer]

Thanks man but didn't actually get the second part

 

[funky brat]

How do we identify if it's stretch or shear? :/

 

[Ram97]

How do we identify if it's stretch or shear? :/

In shear, basically the image is tilted. Shear is the parallel movement along the x-axis
In stretch, the image is enlarged over the object having either a same or different invariant line

 

[Asad.Babur]

Thanks man but didn't actually get the second part

!) The car was decelrating half the speed it was accelrating.......................... So it took it 20 seconds to get the speed U........ It would take it twice (40 Seconds) to get to 0...................................................................................................

So the question asks the time car will take to get the speed U/4, which is quarter its hieghest speeeeeeeeeeeeeeeeeeeeeeeeeeeeeed! .............. So 40 * 3/4 = 30 Seconds

 

[exploded diper]

Thanks man but didn't actually get the second part

I solved it ....

 

[A.Sagheer]

Got it got it.
And if you could please solve the b part of Q27, i'd be grateful.

 

[exploded diper]

Got it got it.
And if you could please solve the b part of Q27, i'd be grateful.

me?