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konsa?koi mjhe vector vla smjhade detail meinnnnn
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konsa?koi mjhe vector vla smjhade detail meinnnnn
Find the perimeter of the sector 90/360*2pierHey, can you do this one?
Q10 (a) (i) of the Paper ON 2013 4024/21:
If you could explain a i to me then It may help me to do the rest of the question:
http://papers.xtremepapers.com/CIE/...Calculator Version) (4024)/4024_w13_qp_21.pdf
http://papers.xtremepapers.com/CIE/...D (Calculator Version) (4024)/4024_w13_er.pdf
Questions karo pehly you'll get wrong phir khud he ajaen gey.koi mjhe vector vla smjhade detail meinnnnn
exploded diper is very very AWESOME
haha yes u r right dudeoh, :'O no, no, thank you, but you are more awesome maths master. I am nothing in front of you. but being praised by such an awesome maths master is really honorable
Oh sorry!how come wen S is d midpoint man
Oh sorry!
PQ = PB + BQ = (9,18)
SQ is half so (4.5,9)
QR is opposite side of PB but in opposite direction so it will be -PB
Add it to SQ to get SR
yeah and u better pay it....ohh no no no dont say tht... u have taught me everything i know......u are the most awesome one indeed....i cannot compare to ur HONESTY ,HUMBLENESS AND GENEROSITY .....i ADMIRE U. I IDOLISE U, U INSPIRE ME..I AM FOREVER IN UR DEBT... i am stupid and u r SHERLOCK
imagine ppl dont get what we r really doing...and they stare at our comments for each other....haha yes u r right dude
meaisay napaak ilfaaz kabhi nahi bol saktayeah and u better pay it....
yes tht we r...meaisay PAAK ilfaaz kabhi nahi bol sakta
btw, we are going off topic
It has changed,the grid is provided and we have to do all working on the question paper.In older days work was on answer sheets and graphs were provided.when it says to answer the questions on a sheet of graph paper is space given for numerical questions not on the grid... or has the format changed?
know what, i've already done this 4 times -.- 1 while solving the ppr myself, the other 3 times for ppl here wait, lemme find that postView attachment 44059
part a ii) Anyone?
Find area of sector,then find area of triangle(1/2absin90) and subtract that.Remaining area multiply by 9.5 to get volumeView attachment 44059
part a ii) Anyone?
I know that. I've seen the MS. But how the hell do I know if I'm supposed to find area in a volume question? :/Find area of sector,then find area of triangle(1/2absin90) and subtract that.Remaining area multiply by 9.5 to get volume
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