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i think grade boundary would be 80% A grafe and 70% B and going DoWn!!!!!
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DAMNit!Eq of circle
(x+5)^2 + (y-9)^2 =25
DAMNit!
I got that tooFor trig i got 56.3 for the tan one (1 solution), and for the other one i got 72,144,216,288.
some of my answers
area garden - 262.5
perimeter - 80.2
area graph - 148/3
minimum point - 4,-28
a^5/8
stationary point is 4 (because x^(3/2) = 8 so x=4 )
area of graph is 128/3 +20/3( because area of second integral can never be negative)
equation of trigonometry solved by completing square but i do not remember answer then 360 - ans
garden qustion : there was someting of 252.5 or something like that )
tan i got something of 93.3 but dont remember if there was another value
perimeter was arc length + 23 +12 + the other side found by cosine rule
The g(Y) was y=1 and y=0.31
stationary point is 4 (because x^(3/2) = 8 so x=4 )
area of graph is 128/3 +20/3( because area of second integral can never be negative)
equation of trigonometry solved by completing square but i do not remember answer then 360 - ans
garden qustion : there was someting of 252.5 or something like that )
tan i got something of 93.3 but dont remember if there was another value
perimeter was arc length + 23 +12 + the other side found by cosine rule
Yeah I think it was 0.37 but it was also 1 didn't they say values???0.37
it was 1 alsoYeah I think it was 0.37 but it was also 1 didn't they say values???
Yeah I think it was 0.37 but it was also 1 didn't they say values???
question had about 13 marks not sure though but if u differentiated correctly and equated the gradient to 0 u will definetly get marks and remember we have the error carried forward by our side so never worryyup except i made a mistake in stationary point wrote x^-3/2 not 3/2 dunno y hhaha so i got y wrong also how many marks for that question?
question had about 13 marks not sure though but if u differentiated correctly and equated the gradient to 0 u will definetly get marks and remember we have the error carried forward by our side so never worry
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