Maths D 22

[Saad Mughal]

It was a rectangle, divided in half. Each side had a right angle, so I divided that in half, formed a hypotenuse and used the tan rule to find AF...which means I took the half of the rectangle as a square..ok wrong move. How'd u find it?

I took variables for AF = x and the smaller triangle height = y,
Then used 138 = Area of Rectangle + Area of Triangle1 + Area of Triangle 2.
The variables y cancelled out (obviously) and I got x=7 cm.

 

[Saad Mughal]

For RV,I and J will be awesome.
That's easy.
Bearing is a bit confusing at times.
No Linear LAW.That's so boring.
Circular Measure,P and C,Coordinate Geometry

Linear law is so lenient in marking! Bearings is easy as well, just remember the basics. Yeah, i and j ones are very easy too.

 

[Heyyy]

It was a rectangle, divided in half. Each side had a right angle, so I divided that in half, formed a hypotenuse and used the tan rule to find AF...which means I took the half of the rectangle as a square..ok wrong move. How'd u find it?

Area of trepezium is what I did and attained the value 7

 

[Heyyy]

BTW,In P1,what was the ratio of the enlarged photo?

 

[Saad Mughal]

BTW,In P1,what was the ratio of the enlarged photo?

1.44:1

 

[Heyyy]

1.44:1

Ahh Thank God.
A friend of mine was telling that it was 1.2 because the photos weren't similar -_-

 

[Saad Mughal]

Ahh Thank God.
A friend of mine was telling that it was 1.2 because the photos weren't similar -_-

Why in the world would they NOT be similar?

 

[Heyyy]

What was the value of SR?

 

[danial 234]

What was the value of SR?

7.5 3 perhaps

 

[Heyyy]

Why in the world would they NOT be similar?

I have no idea.
I asked him what answer he got,he said 1.2 so I said its wrong and maybe you forgot to square the values so he said they weren't similar.

 

[Heyyy]

7.5 3 perhaps

I don't remember my answer but it was x.5 something
x

 

[danial 234]

I don't remember my answer but it was x.5 something
x

are u talking abt the vector ques in p2

 

[Heyyy]

are u talking abt the vector ques in p2

Yup
It was like
(x.5)
( x )
Something

 

[Saad Mughal]

Yeah same as Danial.. It was,
(7.5)
(3.0)

 

[Heyyy]

In the question where they asked if the fence can be longer than 8 meters,the answer was NO,right?
We had to use upperbounds and multiply them,right?

 

[Saad Mughal]

In the question where they asked if the fence can be longer than 8 meters,the answer was NO,right?
We had to use upperbounds and multiply them,right?

Yeah. No. 7.995 was the maximum width of the fence.

 

[Heyyy]

Yes,got the same answer

 

[Saad Mughal]

Er. Was there a part AFTER the surface area calculation in the last question?

 

[Heyyy]

No there wasn't.
Radius one was for 3 marks,are of triangle 2,Volume 1,Cosine one for 4 and S.A 2.
That adds up to 12

 

[Saad Mughal]

No there wasn't.
Radius one was for 3 marks,are of triangle 2,Volume 1,Cosine one for 4 and S.A 2.
That adds up to 12

Oh thank goodness. Phew. I was fretting over the fact that somehow my paper had a missing part.