MATHS HELP (P2)!

[Soulgamer]

AoA, I need help with Question. 4 (b)(iii) & (iv)

and whole (c) part. Help will be highly appreciated

http://www.xtremepapers.me/CIE/Cambridge O Levels/4024 - Mathematics/4024_s04_qp_2.pdf

Need a detailed explanation. Thank You! :good:

 

[Silent Hunter]

IN 4(b)

(iii) just notice that ZCDTY is a pentagon.....and ANGLE TYZ = 108* SO 360-108= 252*

(iv) 108+108+x+x+252=540

x= 36

 

[no.mercy]

@soulgamer its offtopic but can u tell me about battlefield bad company 2 servers in pakistan?

 

[Soulgamer]

IN 4(b)

(iii) just notice that ZCDTY is a pentagon.....and ANGLE TYZ = 108* SO 360-108= 252*

(iv) 108+108+x+x+252=540

x= 36

How come angle TYZ is 108 and can you solve part (c)

 

[Soulgamer]

@soulgamer its offtopic but can u tell me about battlefield bad company 2 servers in pakistan?

Dude Not that I know of any but Saudi servers are awesome and playable.

PS. you have to buy the original game

 

[no.mercy]

@silent yar i couldnt understand (iv) part

@soulgamer you live in pakistan?

 

[ibadsiddiqi]

part iv) ABTYZ is a five sided figure. As the two pentagons ZABTX and ZCDTY are regular, AZY=BTY. so if AZY=x, then 108+108+x+x+252=540. Hence x=36. therefore angle AZY =36

 

[Silent Hunter]

ibad got it correct

 

[Soulgamer]

@silent yar i couldnt understand (iv) part

@soulgamer you live in pakistan?

lol by mistake I hit the thanks button...yeah I live in pak.


And thanks for answering ibad

 

[ibadsiddiqi]

@ soulgamer no problem mate!