-
Prepare by Xtremepapers!
🚀 NEW from the xtremepape.rs team: AI exam prep — 120,000+ worked solutions, and it marks your handwritten working from a photo. Sign in with your forum account & try it free → prepare.xtremepape.rs
maths help
- Thread starter hm12
- Start date
- Messages
- 621
- Reaction score
- 31
- Points
- 28
That's simple as well.
First let me explain the differentiation of this function.
There are two ways to differentiate this:
Firstly you can bring the denominator on the upper side and change it's power to a negative like this:
12[(2x+1)^-2]
Then you can solve it by the method I told you in your other thread.
OR
You can use the product formula to solve it like this:
u/u = {v(du/dx) - u(dv/dx)} DIVIDED BY v^2
------------
Now integration is the anti-derivative or sum of a derivative. So for this question you should bring the denominator on the upper side and change it's power to a negative like this:
12[(2x+1)^-2
Now you can use the formula:
Integral [ (cx^n) dx ] = c { Integral [ (x^n) dx ] }
Meaning you should take 12 as a constant and keep it outside the integral, then integrate (2x+1)^-2.
Show me your attempt and I will help you further!
I hope that helps you!
Don't forget to press the Thanks Button!
First let me explain the differentiation of this function.
There are two ways to differentiate this:
Firstly you can bring the denominator on the upper side and change it's power to a negative like this:
12[(2x+1)^-2]
Then you can solve it by the method I told you in your other thread.
OR
You can use the product formula to solve it like this:
u/u = {v(du/dx) - u(dv/dx)} DIVIDED BY v^2
------------
Now integration is the anti-derivative or sum of a derivative. So for this question you should bring the denominator on the upper side and change it's power to a negative like this:
12[(2x+1)^-2
Now you can use the formula:
Integral [ (cx^n) dx ] = c { Integral [ (x^n) dx ] }
Meaning you should take 12 as a constant and keep it outside the integral, then integrate (2x+1)^-2.
Show me your attempt and I will help you further!
I hope that helps you!
Don't forget to press the Thanks Button!
thats simple.if equation is in the form (ax+b)^n then use this formula for differentiation an(ax+b)^n-1.this is relatively a easy formula 4 such format.But remember do not forget to multiply the constant and this formula is only applicable 4 the given format.
